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notka56 [123]
4 years ago
7

A student wants to make 100 mL of 0.30 M HCl. How many milliliters of 6.0 M HCl is needed to make this solution

Chemistry
1 answer:
sveticcg [70]4 years ago
3 0

Answer:

5mL of 6 M HCl is needed to make 100 mL of 0.3 M of HCl.

Explanation:

Using the dilution formula:

M1V1 = M2V2

M1 = 0.30 M

V1 = 100 mL

M2 = 6.0 M

V2 = unknown

Re-arranging the formula by making V2 the subject of the equation:

V2 = M1V1 / M2

V2 = 0.30 * 100 / 6

V2 = 5 mL

The volume of 6 M of HCl needed to make 0.3 M at 100 mL is 5 mL.

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A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

6 0
3 years ago
how many moles of zinc cholride are produced from the reaction of three moles of xinc and an excess of hydrocholric acid
Leno4ka [110]
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Bello,

I think the answer is A

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4 years ago
Describe the relationship between the mole and molar mass. Be prepared to describe the process for converting between moles and
malfutka [58]

Answer:

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Explanation:

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