The higher in altitude the colder the temperature. Temp. drop 4°F every 1000 feet. That means that 75° at the bottom and 10000 feet up it will be 35°.
This colder temp does affect plant growth but it also affects the soil which in turn affects plant growth. Mountain vegetation (depending on the elevation) is comparable to the vegetation in areas of high latitude. Areas found up in the northern regions are affected by the colder temp as are the soils - same happens in mountainous areas.
You tend to see more evergreens and soils are more acidic and less rich (poor nutrients). You will also get your permafrosts. Eventually a treeline occurs - mountain tops become treeless as does the north arctic areas. You find mosses growing in and around the rocks with some shrubs whereever there is enough soil for the roots to take.
"An increase in altitude, such as climbing a mountain is similar to heading north (in the northern hemisphere) plant and animal species will be similar at a mountain top to those which are further north. "
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The correct answer for the question that is being presented above is this one: "2. are equal to the concentrations of the products." Given the reaction: HC2H3O2(aq) + H2O ↔ H3O+(aq) + C2H3O2-(aq) When the reaction reaches a state of equilibrium, the concentration of product is equal yo the reactant.<span> </span>
Answer:
0.302 moles
Explanation:
Data given
Mass of Pb(NO₃)₂ = 100 g
Moles of Pb(NO₃)₂ = ?
Solution:
To find mole we have to know about molar mass of Pb(NO₃)₂
So,
Molar mass of Pb(NO₃)₂ = 207 + 2[14 + 3(16)]
= 207 + 2[14 + 48]
= 207 + 124
Molar mass of Pb(NO₃)₂ = 331 g/mol
Formula used :
no. of moles = mass in grams / molar mass
Put values in above formula
no. of moles = 100 g / 331 g/mol
no. of moles = 0.302 moles
no. of moles of Pb(NO₃)₂ = 0.302 moles
The equilibrium expression relates the concentrations of the products to the concentrations of the reactants, for the species in solution, this means that it does not use the liquids or solid substances => Keq = [H+] [I-][HOI]<span>. As said, I2 (solid) and H2) (liquid) do not appear in the expression, because as solid and liquids their concentrations do not change.</span>