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4 years ago

A student wants to make 100 mL of 0.30 M HCl. How many milliliters of 6.0 M HCl is needed to make this solution

Chemistry

1 answer:

sveticcg [70]4 years ago

3 0

Answer:

5mL of 6 M HCl is needed to make 100 mL of 0.3 M of HCl.

Explanation:

Using the dilution formula:

M1V1 = M2V2

M1 = 0.30 M

V1 = 100 mL

M2 = 6.0 M

V2 = unknown

Re-arranging the formula by making V2 the subject of the equation:

V2 = M1V1 / M2

V2 = 0.30 * 100 / 6

V2 = 5 mL

The volume of 6 M of HCl needed to make 0.3 M at 100 mL is 5 mL.

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3 years ago

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Answer:

$m_{H_2SO_4}=81.7gH_2SO_4$

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Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

$2Al (s) + 3H_2SO_4 (aq)\rightarrow Al _2(SO4)_3 (aq) + 3H_2 (g)$

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

$m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4$

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

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Best regards.

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