All categories

3 years ago

Try try try please for me please

Chemistry

1 answer:

Inga [223]3 years ago

8 0

Answer:

a.) It is a chemical reaction because a new substance was formed and a colour change occurred in the reaction.

b.) Iron- Metallic element

sulpher- Non-Metalic element

Iron Sulphide- Compound

HOPE IT HELPS....

You might be interested in

I don’t understand how to do this

djverab [1.8K]

Carbon dioxide is a carbon atom and two oxygen atoms, therefore CO2

For the others, they are hydrocarbons.
The first part of the name is determined by how many carbon atoms there are. The second part, is by the type. Alcohol, Alkane, Alkene, alkynes, acid, esters, amides.

7 0

3 years ago

Question 7 unsaved liquid water can store more heat energy than an equal amount of any other naturally occurring substance becau

Paul [167]

Has the highest specific heat.
___________

3 0

3 years ago

A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t

soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K

(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol

0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol

0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol

0.04181L/mol. P = 14.1 L.atm/mol

P = 14.1 L.atm/mol / 0.04181 mol/L

P = 337.2 atm

4 0

3 years ago

Name one chemical property of carbon disulfide

butalik [34]

One carbon and 2 sulfurs

3 0

3 years ago

Cu + 2 AgNO3 + Cu(NO3)2 + 2Ag

Allushta [10]

Answer:

7.28 moles Ag°

Explanation:

Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°

Given 7.28 moles 7.28 moles

To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...

Limiting reactant determination:

Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°

Cu: 7.28 / 1 = 7.28

AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃

Solving Problem depends on AgNO₃; Cu will be in excess.

Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.

5 0

3 years ago