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Thepotemich [5.8K]
3 years ago
12

Write the formula for each of the following. (a) sodium carbonate (b) sodium bicarbonate (c) carbonic acid (d) hydrofluoric acid

(e) sulfur trioxide (f) copper(II) sulfate (g) sulfuric acid (h) hydrosulfuric acid
Chemistry
2 answers:
user100 [1]3 years ago
6 0

(A) Na2CO3

(B) NaHCO3

(C) H2CO3

(D) HF

(E) SO3

(F) CuSO4

(G) H2SO4

(H) H2S

- Remember to place the subscripts correctly. Hope I helped.

galina1969 [7]3 years ago
4 0

Answer:

Have a good day and stay safe!

Explanation:

(a) sodium carbonate - Na2CO3

(b) sodium bicarbonate - NaHCO₃

(c) carbonic acid - H2CO3

(d) hydrofluoric acid - HF

(e) sulfur trioxide - SO3

(f) copper(II) sulfate - CuSO4

(g) sulfuric acid - H2SO4

(h) hydrosulfuric acid -  H2S

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When Niels Bohr refined the model of an atom,what new idea did he include?
pshichka [43]

Answer:

Niels Bohr, refined the model of an atom by proposing a quantized shell structure atomic model in order to describe how the electrons are able to maintain stable orbits around the nucleus

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Explanation:

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3 years ago
Solid ammonium chloride, NH4Cl, is formed by the reaction of gaseous ammonia, NH3, and hydrogen chloride, HCl. NH3(g)+HCl(g)⟶NH4
Mashutka [201]

9.41 atm is the pressure in atmospheres of the gas remaining in the flask

<h3>What is the pressure in atmospheres?</h3>

The equation NH3(g) + HCl(g) ==> NH4Cl(s) is balanced.

Divide the moles of each reactant by its coefficient in the balanced equation, and the limiting reagent is identified as the one whose value is less. With the issue we now have...

6.44 g NH3 times 1 mol NH3/17 g equals 0.3688 moles of NH3 ( 1 = 0.3688)

HCl: 6.44 g of HCl times one mole of HCl every 36.5 g equals 0.1764 moles ( 1 = 0.1764). CONTROLLING REAGENT

NH4Cl will this reaction produce in grams

0.1764 moles of HCl multiplied by one mole of NH4Cl per mole of HCl results in 9.44 g of NH4Cl (3 sig. figs.)

the gas pressure, measured in atmospheres, that is still in the flask

NH3(g) plus HCl(g) results in NH4Cl (s)

0.3688......0.1764............0..........

Initial

-0.1764....-0.1764........+0.1764...Change

Equilibrium: 0.1924.......0...............+0.1924

There are 0.1924 moles of NH3 and no other gases in the flask. This is at a temperature of 25 °C (+273 = 298 °K) in a volume of 0.5 L. After that, we may determine the pressure by using the ideal gas law (P).

PV = nRT

P = nRT/V = 0.1924 mol, 0.0821 latm/mol, and 298 Kmol / 0.5 L

P = 9.41 atm

9.41 atm is the pressure in atmospheres of the gas remaining in the flask

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If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum
monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

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