What is the density of a material if its mass is 32 grams and its volume is 8 milliliters

A mole of oxygen and a mole of hydrogen (at STP) have all of the following in common EXCEPT

Drupady [299]

Answer:

Root mean squared velocity is different.

Explanation:

Hello!

In this case, since we have a mixture of oxygen and nitrogen at STP, which is defined as a condition whereas T = 298 K and P = 1 atm, we can infer that these gases have the same temperature, pressure, volume and moles but a different root mean squared velocity according to the following formula:

$v_{rms}=\sqrt{\frac{3RT}{MM} }$

Since they both have a different molar mass (MM), nitrogen (28.02 g/mol) and oxygen (32.02 g/mol), thus we infer that nitrogen would have a higher root mean squared velocity as its molar mass is less than that of oxygen.

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8 0

3 years ago

Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570

Andrews [41]

x = 1.01

Explanation:

Given equation:

y = 1.2345x – 0.6789

y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

Since we have been given y = 0.570

y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

since y = 0.570

0.57 = 1.2345x – 0.6789

add 0.6789 to both sides;

0.57 + 0.6789 = 1.2345x – 0.6789 + 0.6789

1.2489‬ = 1.2345x

Divide both sides by 1.2345

$\frac{1.2489}{ 1.2345} = \frac{ 1.2345x }{ 1.2345}$

x = 1.01

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7 0

3 years ago

A molecule whose ends have opposite electric charge is call a_?

snow_lady [41]

A polar molecule is a molecule whose ends have opposite electric charges. An example of a polar molecule is H2O or water. Water has 1 side which is positive and the other side which is negative. It is a dipole which means that the two sides are not having the same charges.

5 0

3 years ago

In a hypothetical atom, electron N transitions between energy levels, giving off orange light in the transition. In the same ato

Zielflug [23.3K]

Answer : Electron P has greater energy difference than the Electron N.

Explanation :

Wavelength range of violet light = 400 - 500 nm

Wavelength range of orange light = 600 - 700 nm

The Planck's equation is,

$E=\frac{h\times c}{\lambda}$

where,

E = energy of light

c = speed of light

$\lambda$ = wavelength of light

According to the Planck's equation, wavelength and energy follow inverse relation. As the wavelength increases, energy decreases.

From the given spectrum, the wavelength of violet light is less. We conclude that When electron P gives violet light on transition it means that energy difference between the energy level was high.

From the given spectrum, the wavelength of orange light is more. We conclude that When electron N gives orange light on transition it means that energy difference between the energy level was low.

So, Electron P which gives violet light on transition has greater energy difference than the Electron N.

6 0

3 years ago

Read 2 more answers

Which ionic equation describes a redox reaction? A. Ag(+) + Cl- = AgCl B. 2H(+) + CO3(2-) = CO2 + H2O C. H(+) + OH(-) = H2O D. Z

Gennadij [26K]

Answer: The correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is known as the reaction in which the exchange of electrons takes place.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

From the given ionic reactions:

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

On the reactant side:

Oxidation number of Zn = 0

Oxidation number of Cu = +2

On the product side:

Oxidation number of Cu = 0

Oxidation number of Zn = +2

As the oxidation number of Zn is increasing from 0 to +2. Thus, it is getting oxidized. Similarly, the oxidation number of Cu is decreasing from +2 to 0. Thus, it is getting reduced. Therefore, forming a redox couple

Hence, the correct option is D. $Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

6 0

3 years ago