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3 years ago

Choose if the quantity indicated is a vector or a scalar. Quantity: the number of coins in a piggy bank Type of quantity:

2 answers:

7 0

Vector quantities are always defined by magnitude and its direction.
Here, to define number of coins in a piggy bank, we don't need direction. Hence it is a scalar quantity.

Nataliya [291]3 years ago

4 0

The answer is vector

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A block is at rest on a incline plane as shown in the diagram.As angle is increased, the componet of the blocks weight parallel

Elodia [21]

Answer:

The component of block weight parallel to the plane, Wₓ = W cosθ

Explanation:

Let the weight of the block due to gravitation is W

The direction of the weight is vertically down

Let θ be the angle formed with the vertical weight of the block and the incline.

Taking two components of weight one along the vertical weight and another component perpendicular to it.

Then the component `of weight long the parallel of the plane is

Wₓ = W cosθ

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3 years ago

Explain what happens to the atoms in the reactants during a chemical reaction

xxMikexx [17]

During a chemical reaction, atoms react with each other to form new products. hope this helps (:

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3 years ago

(a) find the magnitude of the gravitational force between a planet with mass 7.50 3 1024 kg and its moon, with mass 2.70 3 1022

anzhelika [568]

<span>The magnitude of the gravitational force between two bodies is the product of their masses divided by the square of the distance between them. So we have F = M1*M2 / r^2. M1 = 7.503 * 10e24 and M2 = 2.703 * 10e22 and r= 2.803 * 10e8; r^2 = 5.606 *10e16. So we have 7.503 *2.703 *10^(24+22) = 20.280 * 10^(46). Then we divide our answer by 5.606 * 10e16 which is the distance ; then we have 3.6175 * 10 e (46- 16) = 3.6175 * 10e30. To find the acceleration we use Newton's second law F = ma. F is 3.6175 * 10e30 and M is 7.503 * 10e24 so a = F/M and then we have 3.6175/7.503 * 10e (30-24) = 0.48 * 10e6. Similarly for moon, we have a = 3.6715/2.703 * 10e(30-22). = 1.358 * 10e8</span>

4 0

3 years ago

A 13,900 N car traveling at 40.0 km/h rounds a curve of radius 1.80 ✕ 102 m.

miss Akunina [59]

a) $0.68 m/s^2$

b) 964.5 N

c) 0.069

Explanation:

When an object is moving in a circular motion, the direction of its velocity is changing - therefore, it has an acceleration towards the center of the circle, called centripetal acceleration.

The magnitude of the centripetal acceleration is given by

$a=\frac{v^2}{r}$

where

v is the speed of the object

r is the radius of the circle

For the car in this problem:

v = 40.0 km/h = 11.1 m/s is the speed

r = 180 m is the radius of the circle

Substituting, we find the acceleration:

$a=\frac{11.1^2}{180}=0.68 m/s^2$

The centripetal force is the force that keeps the object along its circular motion. It also acts towards the center of the circle, and it is given by

$F=ma$

where

m is the mass of the object

a is the centripetal acceleration

Here the weight of the car is

$W=mg=13,900 N$

where

$g=9.8 m/s^2$ is the acceleration due to gravity

So the mass is

$m=\frac{W}{g}=\frac{13,900}{9.8}=1418.4 kg$

Therefore, the centripetal force is

$F=(1418.4)(0.68)=964.5 N$

In this case, the force of static friction between the tires and the road provides the required centripetal force to keep the car in circular motion. This force is given by:

$F_f=\mu mg$