Question

What is the minimum uncertainty in the energy state of an atom if an electron remains in this state for 10 s

Answer 1

Answer:

The minimum uncertainty in the energy state of an atom is $1.0557\times10^{-35}\ J$

Explanation:

Given that,

Time t = 10 s

We need to calculate the minimum uncertainty in the energy state

Using Hisen burg of uncertainty principle equation

$\Delta E\Delta t=\dfrac{h}{2\pi}$

$\Delta E=\dfrac{h}{2\pi}\times\dfrac{1}{\Delta t}$

Where, E = energy

t = time

Put the value into the formula

$\Delta E=\dfrac{6.63\times10^{-34}}{2\times3.14}\times\dfrac{1}{10}$

$\Delta E=1.0557\times10^{-35}\ J$

Hence, The minimum uncertainty in the energy state of an atom is $1.0557\times10^{-35}\ J$