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Verizon [17]
4 years ago
10

At what time will the interfering waves have an amplitude of zero

Physics
2 answers:
nata0808 [166]4 years ago
5 0

Answer:

The answer to the question is 4.00cm

Explanation:

stepladder [879]4 years ago
4 0

When the interfering waves have an amplitude of zero the phenomena is called destructive interference.

It occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions it means that the waves are in 180° different phase from each other.

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A ball is thrown upward and reaches a maximum height of 100m and then returns back to where it was launched. The displacement of
Natalka [10]
The correct answer is
<span>A) 0 m
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In fact, the displacement is a vectorial quantity that corresponds to the difference between the initial and the final position of an object in motion. In this problem, the final position of the ball is equal to its initial position (because the ball returns back to where it was launched), so the displacement of the ball is zero.

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6 0
3 years ago
Read 2 more answers
During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f
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Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

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f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

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8 0
4 years ago
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
What voltage indicates the voltmeter connected to the ends of a conductor, if the ammeter connected in series with this conducto
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Explanation:

V= Current × Resistance

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V= 2000V

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3 years ago
Briefly outline the caloric theory about the nature of heat
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Briefly outline the caloric theory about the nature of heat
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