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d1i1m1o1n [39]
3 years ago
15

Which statement describes the location of metalloids on the periodic table? The metalloids are located below metals and above no

nmetals within a group. The metalloids are located below nonmetals and above metals within a group. The metalloids are located to the right of nonmetals and to the right of metals within a period. The metalloids are located to the left of nonmetals and to the left of metals within a period.
Chemistry
2 answers:
ohaa [14]3 years ago
5 0

<u>Answer:</u> The correct statement is the metalloids are located below nonmetals and above metals within a group.

<u>Explanation:</u>

Metalloids are the chemical elements which shoe the property of both metals and non-metals. There are 7 metalloids in the periodic table: Boron (B), Silicon (Si), Germanium (Ge), Arsenic (as), Antimony (Sb), Tellurium (Te) and Polonium (Po).

These elements are located right to the metals and left to the non-metals in a period and they lie above the metals and below the non-metals in a group.

Hence, the correct statement is the metalloids are located below nonmetals and above metals within a group.

Talja [164]3 years ago
4 0
The metalloids are Boron, Silicon, Geranium, etc and are found to the right of the metals and the left of the nonmetals. Since that is not an option, the best choice would be: The metalloids are located below nonmetals and above metals within a group.
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Answer: 1.61 x 10⁴ kPa

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Pi = xi P

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The mole fraction <u>is defined as the quotient between the moles of solute (ni) and the total moles of the mixture (nt)</u>, which is calculated by adding the moles of all its components:

xi = \frac{n_{i} }{n_{t} }

In the Trimix 10/50 mix you have 10% oxygen, 50% helium and 40% nitrogen.

To calculate the total number of moles of the mixture and thus determine the molar fraction of helium, we consider 100 g and calculate the number of moles that represent 10 g of O₂ (n₁), 50 g of He (n₂) and 40 g of N₂ (n₃):

n₁ =  10 g x \frac{1 mol}{31.998 g} = 0.313 mol

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Then the total number of moles (nt) will be:

nt = n₁ + n₂ + n₃ = 0.313 mol + 6.246 mol +1.428 mol

nt = 7,987 mol

Then, the mole fraction of helium (x₂) in the mixture will be,

x₂ =  \frac{6.246 mol}{7.987 mol} = 0.78

and the partial pressure of helium in the mixture, according to Dalton's law, will be:

P₂ = x₂ P = 0.78 x 2.07 x 10⁴ kPa

P₂= 1.61 x 10⁴ kPa

So, <u>the partial pressure of helium if a tank of trimix 10/50 has a total pressure of 2.07 x 104 kPa is  1.61 x 10⁴ kPa</u>

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