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sasho [114]
3 years ago
8

The old car left on the side of the road showed signs of corrosion. We call this common chemical reaction rusting. The equation

for this reaction can be written as 4Fe + 3O2 → 2Fe2O3. What are the reactants in the rusting process? A) iron oxide B) water and iron C) iron and oxygen Eliminate D) water and iron oxide
Chemistry
2 answers:
masha68 [24]3 years ago
7 0

<u>Answer</u>: Option (C)

<u>Explanation:</u>

The old car left on the side of the road showed signs of corrosion. we call this common chemical reaction rusting. The equation for this reaction can be written as

<h2>4 \mathrm{fe}+3 o_{2} \rightarrow 2 \mathrm{f} e_{2} \mathrm{o}_{3} </h2>

The reactants in the rusting process is iron and oxygen. rusting process is process of converting of metal to a form such as oxides and sulphides.

In  this chemical reaction 4 atoms of iron (fe) combines with 3 molecules of oxygen \left(o_{2}\right)  to form rust, or 2 molecules of iron oxide  (fe_2 o_3), which is a new product.

Alex73 [517]3 years ago
6 0
The answer is C) iron and oxygen. The reactants are on the left side of the equation
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A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release
Marrrta [24]

Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

T_1=20+273=293K\\\\T_2=-40+273=233K

Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

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5 0
3 years ago
WILL GIVE BRAINLIEST!<br> Calculate the bond for CO2
yawa3891 [41]

Answer:

Bonding Order = number of bonding electrons – number of antibonding electrons/2.

So for CO2, there is a total of 16 electrons, 8 of which are antibonding electrons.

So 16 – 8 = 8; divided by 2 = 4. So, 4 is the bonding order of CO2. The molecular structure of CO2 looks like this:

..~-~~..

O=C=O

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5 0
3 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula
Sever21 [200]

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

3 0
3 years ago
Read 2 more answers
Chlorine is used by textile manufacturers to bleach cloth. Excess chlorine is destroyed by its reaction with sodium thiosulfate,
harina [27]
Na2S2O3(aq) + 4Cl2( g) + 5H2O = 2NaHSO4(aq) + 8HCl(aq)

1)How many moles of HCl can form from 0.21 mol of Cl2?
0.21 mol Cl2 ( 8 mol HCl / 4 mol Cl2 ) = 0.42 mol HCl

2)How many moles of H2O are required for the reaction of 0.18 mol of Cl2?
0.18 mol Cl2 ( 5 mol H2O / 4 mol Cl2 ) = 0.225 mol H2O

3)How many moles of H2O react if 0.50 mol HCl is formed?
0.50 mol HCl ( 5 mol H2O / 8 mol HCl ) = 0.3125 mol H2O
6 0
3 years ago
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