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sasho [114]
3 years ago
8

The old car left on the side of the road showed signs of corrosion. We call this common chemical reaction rusting. The equation

for this reaction can be written as 4Fe + 3O2 → 2Fe2O3. What are the reactants in the rusting process? A) iron oxide B) water and iron C) iron and oxygen Eliminate D) water and iron oxide
Chemistry
2 answers:
masha68 [24]3 years ago
7 0

<u>Answer</u>: Option (C)

<u>Explanation:</u>

The old car left on the side of the road showed signs of corrosion. we call this common chemical reaction rusting. The equation for this reaction can be written as

<h2>4 \mathrm{fe}+3 o_{2} \rightarrow 2 \mathrm{f} e_{2} \mathrm{o}_{3} </h2>

The reactants in the rusting process is iron and oxygen. rusting process is process of converting of metal to a form such as oxides and sulphides.

In  this chemical reaction 4 atoms of iron (fe) combines with 3 molecules of oxygen \left(o_{2}\right)  to form rust, or 2 molecules of iron oxide  (fe_2 o_3), which is a new product.

Alex73 [517]3 years ago
6 0
The answer is C) iron and oxygen. The reactants are on the left side of the equation
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A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re
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Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

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Solution:

As  36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

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36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

                 36200 J of heat release ≅ 1 gram of reactant

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Do cross multiplication

              X gram of reactant = 1 g x 1360 J / 36200 J

              X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

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