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3 years ago

How does Pressure affect the solubility of gases?

Chemistry

1 answer:

Rom4ik [11]3 years ago

7 0

Liquids and solids exhibit practically no change of solubility with changes in pressure.

Gases as might be expected, increase in solubility with an increase in pressure.

Henry's Law states that: The solubility of a gas in a liquid is directly proportional to the pressure of that gas above the surface of the solution.

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Fill in the blanks

daser333 [38]

Answer:

Here is the answers I got 8 out of 8 correct :D))

Explanation:

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3 years ago

If an element is in period 5 what do we know about the electron configuration?

Lynna [10]

Answer: Number of energy shells

Explanation:

Periods = no. of shells

Groups = no. of electrons in outer shells

7 0

3 years ago

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken a

Delvig [45]

We know, mole of gas in ideal conditions is 22.414 L
Here, CH4 volume = 8.9L

So, number of moles = 8.9 / 22.414 = 0.397 moles
Here, in balanced equation we have a ratio CH4 : H2O = 1:2.

So, mole so water = , 0.397*2= 0.794 moles
In liters it would be: 0.794 * 22.414 = 17.80 L

In short, Your Answer would be 17.80 Liters

Hope this helps!

8 0

3 years ago

Determine the number of grams of carbon 3.14x 1023 atoms of carbon

tiny-mole [99]

<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 6.26227 \ g \ C$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0

3 years ago

Read 2 more answers

Give the IUPAC name for the following compound. Group of answer choices 6-Ethyl-6-methylhept-3-yne 6,6-Dimethyloct-3-yne 3,3-Dim

slamgirl [31]

Answer:

3,3-Dimethyloct-4-yne · Contents · 1Structures · 2Names and Identifiers · 3Chemical and Physical Properties · 4Related Records · 5 Patents · 6 ..

8 0

3 years ago