Question

A mass of 2 kg of acetylene is in a 0.045 m3 rigid container at a pressure of 4.3 MPa. Use the generalized charts to estimate the temperature.

Answer 1

Answer:

361 K

Explanation:

From the tables:

$P_r=4.3/6.14=0.7,T_c=308.3\ K, R=0.2193\ kJ/kgK\\\\Volume (V)=0.045m^3, mass(m)=2kg\\\\v=V/m=0.045/2=0.0225\ m^3/kg$

Given that:

$v=\frac{ZRT}{P}$

From the charts, at $P_r=0.7,Z_g=0.59,T_r=0.94$

$v_g=\frac{0.59*0.3193*0.94*308.3}{4300}=0.0127\ m^3/kg\ which\ is\ small\\ \\At\ T_r=1,Z=0.7,v=\frac{0.7*0.3193*1*308.3}{4300}=0.016\ m^3/kg\\\\At\ T_r=1.2,Z=0.86,v=\frac{0.86*0.3193*1.2*308.3}{4300}=0.0236\ m^3/kg$

Interpolating, we get $T_r=1.17$, T = 361 K