Answer:
Tara bought a total of 160 treats.
Step-by-step explanation:
We are given the following in the question:
Number of boxes of dog treats = 3
Number of treats in each dog box = 40
Total number of treats in dog box =
![40 \times 3 = 120](https://tex.z-dn.net/?f=40%20%5Ctimes%203%20%3D%20120)
Number of boxes of cat treats = 2
Number of treats in each cat box = 20
Total number of treats in cat box =
![20\times 2 = 40](https://tex.z-dn.net/?f=20%5Ctimes%202%20%3D%2040)
Total number of treats Tara brought =
Total number of treats in dog box + Total number of treats in cat box
![(40\times 3)+(20\times 2)\\= 120 + 40\\=160](https://tex.z-dn.net/?f=%2840%5Ctimes%203%29%2B%2820%5Ctimes%202%29%5C%5C%3D%20120%20%2B%2040%5C%5C%3D160)
Thus, Tara bought a total of 160 treats.
Answer:
<h3>it's the formula for a cylinder. </h3>
Answer:
The null and alternative hypotheses are:
![H_{0}:\mu= 50.07](https://tex.z-dn.net/?f=H_%7B0%7D%3A%5Cmu%3D%2050.07)
![H_{a}:\mu>50.07](https://tex.z-dn.net/?f=H_%7Ba%7D%3A%5Cmu%3E50.07)
Under the null hypothesis, the test statistic is:
![t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5Cbar%7Bx%7D-%5Cmu%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%20%7D)
Where:
is the sample mean
is the sample standard deviation
is the sample size
![=1.26](https://tex.z-dn.net/?f=%3D1.26)
Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:
![t_{critical}=1.833](https://tex.z-dn.net/?f=t_%7Bcritical%7D%3D1.833)
Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.
(10 + x) / (y - 3)....quotient is the result of division