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icang [17]
3 years ago
11

(−8k+1)(−8k+1) standard form

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
7 0

Answer:

64k² - 16k + 1

Step-by-step explanation:

(−8k+1)(−8k+1)

64k² - 8k - 8k + 1

64k² - 16k + 1

kifflom [539]3 years ago
3 0

Answer:

64k^2 - 16k +1

Step-by-step explanation:

We can rewrite this as

(-8k+1) ^2

We know that (a+b)^2 = a^2 +2ab +b^2

Let a = -8k  and b = 1

(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2

           =64k^2 - 16k +1

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3 years ago
A = {1, 2, 5, 7}B = {3, 4, 6, 7}C = {0, 5, 8, 9}
Feliz [49]

A U B = {1, 2, 3, 4, 5, 6, 7}

Step-by-step explanation:

  • Step 1: Find A U B. Union of two sets A and B are the set of all elements in set A and set B.

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Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
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Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

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The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

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x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

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J(2,2)

K(6,2)

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