Probability of finding no defective bulb
=95/100*94/99....86/91
=95!/(85!) / (100!/90!)
= 110983/190120
=>
Probability of finding at least one defective bulb
=1-110983/190120
= 79137/190120
= 0.41625 (to 5 decimal places)
Answer:
5,10,15,20... is A). 20,17,14,11... is B). 1,3,9,27... is C). and 128,32,8,2 is D)
Step-by-step explanation:
plug in each common difference/ common ratio with each set to see what works
Answer:
Rational number as denominator is not equal to zero and numerator is a integer.
Answer:
42
Step-by-step explanation:
5 more than 2 times the girls
89=5+2x
x=42
