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3 years ago

(−8k+1)(−8k+1) standard form

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer:

64k² - 16k + 1

Step-by-step explanation:

(−8k+1)(−8k+1)

64k² - 8k - 8k + 1

64k² - 16k + 1

kifflom [539]3 years ago

3 0

Answer:

64k^2 - 16k +1

Step-by-step explanation:

We can rewrite this as

(-8k+1) ^2

We know that (a+b)^2 = a^2 +2ab +b^2

Let a = -8k and b = 1

(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2

=64k^2 - 16k +1

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2 years ago

Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol

Zigmanuir [339]

Answer:

$672\pi \text{ cm}^3$ .

Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.

We will use volume formula of sphere to solve our given problem.

$\text{Volume of sphere}=\frac{4}{3}\pi r^3$ , where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

$\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3$

$\text{Difference of volumes}=4\pi(168)\text{ cm}^3$

$\text{Difference of volumes}=672\pi\text{ cm}^3$

Therefore, the difference between volumes of the spheres is $672\pi \text{ cm}^3$ .

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4 years ago

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attashe74 [19]

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3 years ago

Find the value of q^2, when q= -10

ikadub [295]

If q = -10

Then:
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3 years ago

Read 2 more answers

Help. I got it wrong and have no clue how to get to the right answer!

natima [27]

$\bf 2x+\sqrt{4x^2}+\sqrt[3]{8x^3}\qquad 
\begin{cases}
4\to 2^2\\
8\to 2^3
\end{cases}\qquad thus
\\\\\\
2x+\sqrt{2^2x^2}+\sqrt[3]{2^3x^3}\implies 2x+\sqrt{(2x)^2}+\sqrt[3]{(2x)^3}
\\\\\\
2x+2x+2x=\boxed{6x}$

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3 years ago