Answer:
Step-by-step explanation:
The volume of the solid revolution is expressed as;
Given y = 2x²
y² = (2x²)²
y² = 4x⁴
Substitute into the formula
![V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E2_0%20%7B4%5Cpi%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D4%5Cpi%20%5Cint%5Climits%5E2_0%20%7B%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D%204%20%5Cpi%20%5B%5Cfrac%7Bx%5E5%7D%7B5%7D%20%5D%5C%5C)
Substituting the limits
![V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3](https://tex.z-dn.net/?f=V%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B2%5E5%7D%7B5%7D%5D%20-%20%5B%5Cfrac%7B0%5E5%7D%7B5%7D%5D%29%5C%5CV%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B32%7D%7B5%7D%5D%20-%200%29%5C%5CV%20%3D%20128%20%5Cpi%2F5%20units%5E3)
Hence the volume of the solid is
The explicit formula of the sequence is given by a_n = -4n(n-1).
We have to find the first five terms of the sequence.
The first term:
The second term:
The third sum:
The fourth term:
The fifth term:
Thus, option D is correct.
Answer:700,000+80,000+4,000+200+20+9
Step-by-step explanation:
That should be the answer.
1) The best thing to do here is to divide the two weights of the buses and fin out what you need to multiply it by.
100/50= 2.
Therefore, you've got to multiply the amount of people by 2.
10*2= 20
Therefore, it takes 20 people to pull a 100 ton bus.
2) Here, you should work out what each one is worth. Half of 40 is 20.
one fourth of 20 is 5. Therefore, half of 40 is larger.
3) The best thing to do is to divide 32 by 8, and then multiply the number of degrees by this.
32/8=4
110*4= 440
Therefore, the ball rotates 440 degrees in 32 seconds.
4) the best thing to do is to find what one part is worth- and to do this, you have to add together the amount of roses and divide this by the total roses.
4+6= 10
50/10= 5
The roses are 6 parts yellow, therefore, 6*5= 30, there are 30 yellow roses.
Hope this helps :)
Answer:
option 1 is the answer of your question
