Answer:
Step-by-step explanation:
B(2,10); D(6,2)
Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)
Rhombus all sides are equal.
AB = BC = CD =AD
distance = √(x2-x1)² + (y2- y1)²
As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x
A(X,0)
AB = AD
√(2-x)² + (10-0)² = √(6-x)² + (2-0)²
√(2-x)² + (10)² = √(6-x)² + (2)²
√x² -4x +4 + 100 = √x²-12x+36 + 4
√x² -4x + 104 = √x²-12x+40
square both sides,
x² -4x + 104 = x²-12x+40
x² -4x - x²+ 12x = 40 - 104
8x = -64
x = -64/8
x = -8
A(-8,0)
Let C(a,b)
M is AC midpoint
(-8+a/2, 0 + b/2) = M(4,6)
(-8+a/2, b/2) = M(4,6)
Comparing;
-8+a/2 = 4 ; b/2 = 6
-8+a = 4*2 ; b = 6*2
-8+a = 8 ; b = 12
a = 8 +8
a = 16
Hence, C(16,12)
Answer: desktop = $1750, laptop = $1900
<u>Step-by-step explanation:</u>
Let x represent the cost of the desktop
then x + 150 is the cost of the laptop.
.07x + .055(x + 150) = 227
.07x + .055x + 8.25 = 227
.125x = 218.75
x = 1750
desktop (x) = $1750
laptop (x + 150) = $1750 + $150 = $1900
(5,12,13) is a right triangle and can be constructed.
All the others do not satisfy the triangle inequality, i.e. the sum of two short sides must exceed the long side in order for the triangle to be constructed.
Examples:
2+11<15, so no
3+7<11, so no
4+8<15, so no
but 5+12>13 so yes, it can be constructed.
Answer:
-23 degree
Step-by-step explanation:
=>-14-5-3-1
=>-23
Answer:
The given functions are not same because the domain of both functions are different.
Step-by-step explanation:
The given functions are
First find the domain of both functions. Radicand can not be negative.
Domain of f(x):
This is possible if both numerator or denominator are either positive or negative.
Case 1: Both numerator or denominator are positive.
So, the function is defined for x≥1.
Case 2: Both numerator or denominator are negative.
So, the function is defined for x≤-1.
From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).
Domain of g(x):
So, the function is defined for x≥1.
So, domain of g(x) is [1,∞).
Therefore, the given functions are not same because the domain of both functions are different.
