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kipiarov [429]
3 years ago
14

Graph y=-x-6 YOU WILL BE MARK BRAINLIEST

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0
Look at the attachment

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Identify the parameters p and n in the following binomial distribution scenario. Jack, a bowler, has a 0.38 probability of throw
Elanso [62]

Answer:

p = 0.38, n = 20

The probability that he throws more than 10 strikes = 0.09233

Step-by-step explanation:

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of times Jack wants to bowl = 20

x = Number of successes required = number of strikes he intends to get

p = probability of success = probability that Jack throws a strike = 0.38

q = probability of failure = probability that Jack doesn't throw a strike = 0.62

P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)

P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)

P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)

P(X > 10) = 0.09233

There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.

8 0
3 years ago
200 3. A technician charges $25 per hour plus $50 for a house call to repair home computers. Make a table and a graph to show th
Tju [1.3M]

Recall that for a home visit, the technician charges $50 regardless on the time spent in the repair.

So, to find out the rate, we should calculate the part that depends on the spent time, and the add 50. So for example, we know that the technician spents 1 hour. So, we multiply 1 times 25 and then add 50. So, 25*1 + 50 = 75, which is the rate for a 1-hour repair.

So, in general, if we know that the number of hours is x, we multiply x times 25 and then add 50. Then a table would like this:

x 25*x 25*x +50

1 25 75

2 50 100

3 75 125

4 100 150

Note that as the time increases by one hour, the fare increases by 25. This is an example of a direct variation, since as the independent variable increases (t

6 0
1 year ago
A total of 200 10-year-old children of similar intellectual abilities participated in a noise experiment in their classrooms. Th
Vladimir79 [104]

Answer:

The dependent variable for this experiment is the ability of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment which depends on the presence or absence of noise outside the classroom.

Step-by-step explanation:

In an experiment, the independent variable is the one whose value, form or outcome is not determined by any other variable in the experiment.

The dependent variable is the one whose value, form or outcome is determined by one or more other variable(s) in the experiment.

This experiment tests the abilities of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment.

This ability was made to depend on whether there was noise or no noise outside their classrooms.

Since, this variable to be measured is determined by another variable in the experiment, it is evident that this is the dependent variable for this experiment.

Hope this Helps!!!

6 0
3 years ago
What is the value of c in the equation below?! HELP
prisoha [69]

Note that when dividing, and the base is the same, you can subtract the power signs.

(5^5)/(5^2) = 5^(5 - 2)

5 - 2 = 3

5^3 = a^b

Simplify.

5^3 = 5 x 5 x 5

5 x 5 x 5 = 125

c = 125

----------------------------------------------------------------------------------------------------------------

125 is your answer

----------------------------------------------------------------------------------------------------------------

hope this helps

8 0
3 years ago
Read 2 more answers
Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too?
rusak2 [61]

<em>Question 5</em>

Vertical angles are <u>congruent</u>. Therefore, 3y=\boxed{150}. The sum of two supplementary angles equals \boxed{180^{\circ}}.

Therefore, 6x+150=\boxed{180}

<em>Question 6</em>

\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}

<em>Question 7</em>

<em />\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}

<em>Question 8</em>

<em />7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}

6 0
1 year ago
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