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stellarik [79]
3 years ago
14

The diagram below is an artist’s impression of a single atom of element Be. The neutrons are shown with stripes, the protons are

gray, and the electrons are black. These particles are not drawn to scale.
Which element below could be an isotope of this atom?
Need Help Asap! please and thank you.

A.sodium-10
B.beryllium-10
C.boron-9
D.carbon-9

Chemistry
1 answer:
lara [203]3 years ago
8 0
The correct option is B.
Isotopes refers to those chemical compounds which have the same number of protons and electrons but different number of neutrons, so they end up having different mass numbers.  The diagram given above is that of beryllium, which has atomic number 4 and it has 2 electrons in its outermost shell. It has four protons [same as the number of electrons] and 5 neutrons. Beryllium 10, which is its isotope has four electrons, four protons and 6 neutrons. To get the number of neutron, remove the number of electrons from the number given in the option, that is, 10 - 4 = 6.
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<h3><u>Answer</u>;</h3>

A. When a reaction is at chemical equilibrium, a change in the system will cause the system to shift in the direction that will balance the change and help the reaction regain chemical equilibrium.

<h3><u>Explanation</u>;</h3>
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cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

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Explanation:

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