Answer:
<h3>The answer is 2800 kg</h3>Explanation:
The mass of the truck can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>2800 kg</h3>Hope this helps you
Car A rear ends Car B, which has twice the mass of A, on an icy road at a speed low enough so that the collision is essentially
1 answer:
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a)
Here the crate is moving at constant velocity, so no acceleration:
a = 0
Let's analyze the forces acting along the horizontal and vertical direction.
- Vertical direction: the equation of the forces is
(1)
where
R is the normal reaction of the floor (upward)
is the component of the force F in the vertical direction (downward)
mg is the weight of the crate (downward)
- Horizontal direction: the equation of the forces is
(2)
where
is the horizontal component of the force F (forward)
is the force of friction (backward)
From (1) we get
And substituting into (2)
b)
In this second case, the crate is still at rest, so we have to consider the static force of friction, not the kinetic one.
The equations of the forces will be:
(1)
(2)
In this second case, we want to find the critical value of such that the woman cannot start the crate: this means that the force of friction must be at least equal to the component of the force pushing on the horizontal direction,
.
Therefore, using the same procedure as before,
And solving for ,
Now we analyze the expression that we found. We notice that if the force applied F is very large, , therefore we can rewrite the expression as
So, this is the critical value of the coefficient of static friction.
Answer:
The magnitude of the magnetic field vector is 1.91T and is directed towards the east.
The steps to the solution can be found in the attachment below.
Explanation:
For the charge to remain in the the earth' gravitational field the magnetic force on the charge must be equal to the earth's gravitational force on the charge and must act opposite the direction of the earth's gravitational force.
Fm = Fg
qvBSin(theta) = mg
Where q = magnitude of charge
v = magnitude of the velocity vector = 4 x10^4 m/s
B = magnitude of the magnetic field vector
theta = the angle between the magnetic field and velocity vectors = 90°
m = mass of the charge = 0.195g
g = acceleration due to gravity =9.8m/s²
On substituting the respective values of all variables in the equation (1) above
B = 1.91T
The direction of the magnetic field vector was found by the application of the right hand rule: if the thumb is pointed in the direction of the magnetic force and the index finger is pointed in the direction of the velocity vector, the middle finger points in the direction of the magnetic field.
Below is the step by step procedure to the solution.
