Which element is found in all the acids described in this section?

Why does Australia get more UV light than the other parts of the world?

Nataly [62]

During summer, the Earth's orbit brings Australia closer to the sun (as compared to Europe during its summer), resulting in an additional 7% solar UV intensity. Coupled with our clearer atmospheric conditions, this means that Australians are exposed to up to 15% more UV than Europeans.

7 0

3 years ago

Colloids are true solutions. <br><br><br> ____ True ____ False

Reptile [31]

This is false, they have intermediate properties between suspension and true solution

7 0

3 years ago

Read 2 more answers

Is cholate milk homo or hetero mixture

Harlamova29_29 [7]

It's a homogeneous mixture because when it is mixed together you can no longer tell which parts are chocolate or which parts are milk

8 0

4 years ago

with an excess of oxygen gas according to the following chemical equation. 4 P 502 > 2 P2Os What mass of P2O5 can be produced

MArishka [77]

Answer:

394.76g

Explanation:

Given parameters:

Mass of Phosphorus = 172.1g

Unknown:

Mass of P₂O₅ = ?

Solution:

We should work from the known specie to the unknown in this problem. The limiting reactant is the reactant in short supply and it determines the extent of the reaction. This is the given phosphorus.

Oxygen is in the excess.

The balanced reaction equation:

4P + 5O₂ → 2P₂O₅

let us find the number of moles of phosphorus first,

Number of moles of phosphorus = $\frac{mass}{molar mass}$

Molar mass of phosphorus = 31g/mole

Number of moles = $\frac{172.1}{31}$ = 5.55mole

4 moles of phosphorus gives 2 moles of P₂O₅

5.55 mole of P will produce $\frac{5.55 x 2}{4}$ = 2.78moles

Mass of P₂O₅ = number of moles x molar mass

Molar mass of P₂O₅ = (31 x 2) + (16 x 5) = 142g/mole

Mass of P₂O₅ = 2.78moles x 142g/mole = 394.76g

4 0

3 years ago

Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C

Leno4ka [110]

Explanation:

The reaction equation will be as follows.

$C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)$

Using bond energies, expression for calculating the value of $\Delta H$ is as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

On reactant side, from $C_{2}H_{6}$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From $Cl_{2}$ ; Cl-Cl bonds = 1

On product side, from $C_{2}H_{5}Cl$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

= $[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]$ = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0

3 years ago