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shusha [124]
3 years ago
6

g Determine the value of the equilibrium constant for this reaction if an initial concentration of N2O4(g) of 0.040 mol/L is red

uced to 0.0055 mol/L at equilibrium. There is no NO2(g) present at the start of the reaction.
Chemistry
1 answer:
jeyben [28]3 years ago
7 0

Answer:

Explanation:

N₂O₄(g) ⇄ 2 NO₂

N₂O₄ reacted = .04 - .0055 = .0345 mole

NO₂ formed = 2 x .0345 = .069 moles

equilibrium constant = [ NO₂ ] ² / [ N₂O₄]

= .069² / .0055

= 0.865 .

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It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g
dimulka [17.4K]

Answer:

0.1g (Gallon) of chlorine

Explanation:

<u>Formula</u>

1 gallon = 3.7L; the density of water is 1.0g/ml

<u>Given</u>

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

<u>Solve</u>

If 2g (gallon) chlorine = 1,000,000g (gallon)

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The First step; set up an equation

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The Next step; divide 1 million to 2

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Then, divide the result by 40000

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Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

7 0
2 years ago
Read 2 more answers
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