g Determine the value of the equilibrium constant for this reaction if an initial concentration of N2O4(g) of 0.040 mol/L is red
uced to 0.0055 mol/L at equilibrium. There is no NO2(g) present at the start of the reaction.
1 answer:
Answer:
Explanation:
N₂O₄(g) ⇄ 2 NO₂
N₂O₄ reacted = .04 - .0055 = .0345 mole
NO₂ formed = 2 x .0345 = .069 moles
equilibrium constant = [ NO₂ ] ² / [ N₂O₄]
= .069² / .0055
= 0.865 .
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