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2 years ago

What are the freezing and boiling points of water on the celsius temperature table

2 answers:

4 0

There are 100 degrees between the freezing (0°) and boiling points (100°) of water on the Celsius scale and 180 degrees between the similar points (32° and 212°) on the Fahrenheit scale.

Problem: Two scientists are doing an experiment designed to identify the boiling point
Answer: 250°F is the higher temperature by 2°F

Evgesh-ka [11]2 years ago

4 0

Answer:

freezing point is 0°C and boiling point is 100°C

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a sample of copper wire with a mass of 1.659 g is heated with excess powdered sulfur until the copper has combined with the sulf

BabaBlast [244]

Copper mass = 1.659
Copper moles = 1.659 / 64 = 0.0259

Sulfur mass = 2.08 - 1.659 = 0.421
Sulfur moles = 0.421 / 32 = 0.0131

Ratio Copper : Sulfur = 2 : 1

Empirical formula: Cu ₂ S
Name: Copper (I) sulfide

7 0

4 years ago

Which Cl isotope should we use to get the atomic mass of the element Cl?

Sati [7]

Answer:

i think it's B CI-35 only

Explanation:

hope this helps

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3 years ago

Electron configuration of Phosphorus

Aleks [24]

1s^2 2s^2 2p^6 3s^2 2p^3 or the shortcut way is [Ne] 3s^2 2p^3

3 0

4 years ago

What is the difference between an atom in the ground state and an atom in an excited state? A. The atom in the ground state has

Marizza181 [45]

The correct option is C.

An atom can be either in the ground state or in an excited state. An atom is said to be in the ground state, if the total energy of its electron can not be lowered by moving one or more electrons into different orbitals. At the ground state, the electrons in the atom have the lowest energy possible and they are stable. On the other hand, an atom is said to be in an excited state, if the energy of its electrons can be lowered by transferring one or more electrons into different orbitals. An atom in an excited state has more energy and is less stable.

7 0

4 years ago

Read 2 more answers

What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 187 mL to make a 1.53 M solution of

Len [333]

Answer:

47.68 mL

Explanation:

In this case, we have a dilution problem. So, we have to start with the dilution equation:

$C_1*V_1=C_2*V_2$

We have to remember that in a dilution procedure we go from a higher concentration to a lower one. With this in mind, We have to identify the concentration values:

$C_1~=~6.00~M$

$C_2~=~1.53~M$

The higher concentration is C1 and the lower concentration is C2. Now, we can identify the volume values:

$V_1~=~X$

$V_2~=~187~mL$

The V2 value has "mL" units, so V1 would have "mL" units also. Now, we can include all the values into the equation and solve for "V1", so:

$6.00~M*V_1=1.53~M*187~mL$

$V_1=\frac{1.53~M*187~mL}{6.00~M}=47.68~mL$

So, we have to take 47.68 mL of the 6 M and add 139.31 mL of water (187-47.68) to obtain a solution with a final concentration of 1.53 M.

I hope it helps!

6 0

3 years ago