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inn [45]
3 years ago
13

How could dumping pollutants, such as motor oil, in your driveway be hazardous to the neighbor 20 miles away?

Chemistry
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

C

Explanation:

Finding a new water source would be quite difficult

Leokris [45]3 years ago
5 0
C and D

if you are only able to choose you can choose any one one (C or D)
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How does Controlled fires help prevent real forest fires?
Salsk061 [2.6K]

Answer:

it burns things which would be burned easily by lightning, and then people put the fire out immediately.  If the dried plants that they are lighting on fire are hit by lightning, it can lead to a massive fire without anyone realizing.  

6 0
3 years ago
What is the difference between conjugate acid-base pair?
NeX [460]

Answer:

B. a H+ ion is the answer dear.

Explanation:

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5 0
3 years ago
If the plum pudding model of the atom was correct, what should the results of Rutherford’s experiment be?
shusha [124]

Answer:most of the positively charge particles should be bounce back at a range of angles as they collide with the atoms in the foil; only a few should pass straight through the foil

Explanation:

6 0
3 years ago
Can someone help me please?<br> Why can’t you see individual atoms without special tools?
natta225 [31]

Answer:

Even the most powerful light-focusing microscopes can't visualise single atoms. What makes an object visible is the way it deflects visible light waves. Atoms are so much smaller than the wavelength of visible light that the two don't really interact. To put it another way, atoms are invisible to light itself.

Explanation:

Can you give me Brainliest pls

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8 0
3 years ago
Read 2 more answers
Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec
Svetach [21]

The overall reaction is given by:

Br_{2}(g) + 2 NO(g) \rightarrow  2 NOBr(g)

The fast step reaction is given as:

NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})

The slow step reaction is given as:

NOBr_{2}(g) + NO(g) \rightarrow  2 NOBr(g) (slow step k_{2})

Now, the expression for the rate of reaction of fast reaction is:

r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]

The expression for the rate of reaction of slow reaction is:

r_{2}=k_{2}[NOBr_{2}] [NO]

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as [NOBr_{2}] takes place in this reaction.

The expression of rate of formation is:

\frac{d(NOBr)}{dt}=r_{2}

= k_{2}[NOBr_{2}][NO]    (1)

Now, consider that the fast step is always is in equilibrium. Therefore, r_{1}=0

k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]

[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]

Substitute the value of [NOBr_{2}] in equation (1), we get:

\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]

=k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]

= \frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]

Thus, rate law of formation of NOBr in terms of reactants is given by \frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}].









4 0
3 years ago
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