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4 years ago

Besides the force due to gravity or g, what else determines the period of a pendulum?

2 answers:

8 0

The period of a pendulum is determined by the length of the cord and the acceleration of gravity where the pendulum is located.

Shtirlitz [24]4 years ago

8 0

Answer:

Option (C)

Explanation:

The time period of simple pendulum is defined as the time taken by the bob to complete one oscillation.

The formula to calculate the time period of a simple pendulum is given by

$T = 2\pi \sqrt{\frac{l}{g}}$

Time period depends on the acceleration due to gravity and the effective length of the pendulum.

The effective length is the sum of length of cord and the radius f bob.

The effective length of the pendulum is defined as the distance between the point of suspension and the centre of gravity of the bob.

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3 years ago

An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra

lukranit [14]

Answer:

$\frac{dA}{dt} = 28800 \ m^2/year$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Area of a Rectangle: A = lw

Algebra I

Exponential Property: $w^n \cdot w^m = w^{n + m}$

Calculus

Derivatives

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Area is A = lw

2w = l

w = 300 m

$\frac{dw}{dt} = 24 \ m/year$

Step 2: Rewrite Equation

Substitute in l: A = (2w)w
Multiply: A = 2w²

Step 3: Differentiate

Differentiate the new area formula with respect to time.

Differentiate [Basic Power Rule]: $\frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}$
Simplify: $\frac{dA}{dt} = 4w\frac{dw}{dt}$

Step 4: Find Rate

Use defined variables

Substitute: $\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)$
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Multiply: $\frac{dA}{dt} = 28800 \ m^2/year$

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3 years ago

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A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?

kolezko [41]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

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3 years ago