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vlada-n [284]
4 years ago
15

Besides the force due to gravity or g, what else determines the period of a pendulum?

Physics
2 answers:
Naily [24]4 years ago
8 0

The period of a pendulum is determined by the <em>length of the cord</em> and the acceleration of gravity where the pendulum is located.

Shtirlitz [24]4 years ago
8 0

Answer:

Option (C)

Explanation:

The time period of simple pendulum is defined as the time taken by the bob to complete one oscillation.

The formula to calculate the time period of a simple pendulum is given by

T = 2\pi \sqrt{\frac{l}{g}}

Time period depends on the acceleration due to gravity and the effective length of the pendulum.

The effective length is the sum of length of cord and the radius f bob.

The effective length of the pendulum is defined as the distance between the point of suspension and the centre of gravity of the bob.

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An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra
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Answer:

\frac{dA}{dt} = 28800 \ m^2/year

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

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<u>Algebra I</u>

  • Exponential Property: w^n \cdot w^m = w^{n + m}

<u>Calculus</u>

Derivatives

Differentiating with respect to time

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Explanation:

<u>Step 1: Define</u>

Area is A = lw

2w = l

w = 300 m

\frac{dw}{dt} = 24 \ m/year

<u>Step 2: Rewrite Equation</u>

  1. Substitute in <em>l</em>:                    A = (2w)w
  2. Multiply:                              A = 2w²

<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

  1. Differentiate [Basic Power Rule]:                                                                   \frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}
  2. Simplify:                                                                                                           \frac{dA}{dt} = 4w\frac{dw}{dt}

<u>Step 4: Find Rate</u>

<em>Use defined variables</em>

  1. Substitute:                    \frac{dA}{dt} = 4(300 \ m)(24 \ m/year)
  2. Multiply:                        \frac{dA}{dt} = (1200 \ m)(24 \ m/year)
  3. Multiply:                        \frac{dA}{dt} = 28800 \ m^2/year
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A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?
kolezko [41]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

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u= 0m/s

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Step two:

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t= 30/23

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acceleration= 23/1.30

accelaration= 17.69 m/s^2

3 0
3 years ago
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