All categories

4 years ago

If a man weighs 900 n on the earth, what would he weigh on jupiter, where the acceleration due to gravity is 25.9 m/s2?

1 answer:

4 0

<span>So, if the man weight 900 newtons on Earth then that means, using F=ma, that the mass of the man is approximately 91.84 kg. This is because 900N=m(9.8m/s^2), and so it follows that 900/9.8=91.84. Using the man's found mass we then plug this into F=ma again. It follows that F=(91.84)(25.9)=2378.57N. This means that the man "weighs" 2378.57 Newtons on Jupiter, or about 2.5x as great as his weight on Earth. This makes sense, considering that 25.9/9.8 is approximately equal to 2.64.</span>

You might be interested in

H2O Cl2 NH3 What do all of these compounds have in common? A) They are all ionic. B) They are all covalent. C) They all are posi

harkovskaia [24]

B. They are all covalent

5 0

4 years ago

What is the name of this atom? I

Vilka [71]

Answer:

cerro azul

Explanation:

I reverse image searched and it popped up with a name.

5 0

3 years ago

Read 2 more answers

Which of the sites on this cross section would be the most likely place for a spring?

valentina_108 [34]

Had to look for the given illustration attached to this question and here is my answer. The site on the cross section provided wherein it is the most likely place for a spring would be SITE C. In the image, it is labeled sites A, B, C, and D. Hope this answers your question.

4 0

3 years ago

HELP PLZ

Agata [3.3K]

Answer:

40*C

Explanation:

5 0

3 years ago

Depict the following path: You drive 14 blocks East, 7 blocks North, and 2 blocks West. Use the vertex of the graph (coordinates

horrorfan [7]

Answer:

Displacement = $12\hat{i} +7\hat{j}$

Magnitude of displacement = 13.89 units

Angle of displacement = 30.26°

Explanation:

Mark the co-ordinates of each of the end points of the vectors.

The marked co-ordinates are shown below.

Displacement is the shortest distance between two points. Here, displacement between the starting and end points is the vector $\overrightarrow{OA}$ .

Displacement vector for a point A $(x,y)$ from origin O is given as:

$\overrightarrow{OA}=(x-0)\hat{i}+(y-0)\hat{j}$

Magnitude is given as:

$|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}$

Direction of the vector is given as:

$\theta=tan^{-1}\frac{y}{x}$

Therefore, displacement vector is:

$\overrightarrow{OA}=(12-0)\hat{i}+(7-0)\hat{j}\\ \overrightarrow{OA}=12\hat{i}+7\hat{j}$

Magnitude of displacement is given as:

$|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}\\ |\overrightarrow{OA}|=\sqrt{12^{2}+7^{2}}\\ |\overrightarrow{OA}|=\sqrt{144+49}\\\\ |\overrightarrow{OA}|=13.89$

Angle of displacement is:

$tan\theta=\frac{y}{x} =\frac{7}{12}\\\theta=tan^{-1}(\frac{7}{12})$

$\theta=30.26$ °

8 0

4 years ago