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3 years ago

A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?

Physics

1 answer:

kolezko [41]3 years ago

3 0

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

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Answer:

Mass of the vehicle and small bug.

Explanation:

By Newton's third law, force on bug and vehicle will be same when they collide with each other irrespective of their masses.

But according to Newton's second law, force is mass times acceleration. Since the force on each mass is same, the smaller mass will accelerate more and the heavier mass will accelerate less for the same force.
Therefore the acceleration of bug will be very greater than vehicle as the mass of the bug is very small as compared to vehicle.

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3 years ago

A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of

Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

$F=ILB sin \theta$

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

$\theta$ is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

L = 5 m

$\theta=90^{\circ}$

Substituting into the equation, we find

$F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N$

6 0

3 years ago

URGENT!!!!! If a 6 Ω resistor is in a circuit connected to a voltage source, and the current through the circuit is 2 amps, what

Eduardwww [97]

Answer:

Explanation:

according to ohms law we know that

v=IR

given current =2 amps

given resistance =6Ω

so voltage is

v=2*6 =12 V

3 0

4 years ago

A piston of volume 0.1 m3 contains two moles of a monatomic ideal gas at 300K. If it undergoes an isothermal process and expands

seropon [69]

Answer:

the work is done by the gas on the environment -is W= - 3534.94 J (since the initial pressure is lower than the atmospheric pressure , it needs external work to expand)

Explanation:

assuming ideal gas behaviour of the gas , the equation for ideal gas is

P*V=n*R*T

where

P = absolute pressure

V= volume

T= absolute temperature

n= number of moles of gas

R= ideal gas constant = 8.314 J/mol K

P=n*R*T/V

the work that is done by the gas is calculated through

W=∫pdV= ∫ (n*R*T/V) dV

for an isothermal process T=constant and since the piston is closed vessel also n=constant during the process then denoting 1 and 2 for initial and final state respectively:

W=∫pdV= ∫ (n*R*T/V) dV = n*R*T ∫(1/V) dV = n*R*T * ln (V₂/V₁)

since

P₁=n*R*T/V₁

P₂=n*R*T/V₂

dividing both equations

V₂/V₁ = P₁/P₂

W= n*R*T * ln (V₂/V₁) = n*R*T * ln (P₁/P₂ )

replacing values

P₁=n*R*T/V₁ = 2 moles* 8.314 J/mol K* 300K / 0.1 m3= 49884 Pa

since P₂ = 1 atm = 101325 Pa

W= n*R*T * ln (P₁/P₂ ) = 2 mol * 8.314 J/mol K * 300K * (49884 Pa/101325 Pa) = -3534.94 J

5 0

3 years ago

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damaskus [11]

It is the Geothermal Nuclear Energy

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3 years ago

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