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-Dominant- [34]
3 years ago
13

A wire is wrapped multiple times around a galvanized or aluminum nail and then each end of the wire connected to a battery for s

ome period of time. what happens when the nail is then positioned next to a paper clip and why?
Physics
2 answers:
galina1969 [7]3 years ago
6 0
Its A The paper clip is repelled away from the nail because an electromagnetic field magnetized to the nail
Artemon [7]3 years ago
6 0

Hello. This question is incomplete. The full question is:

"A wire is wrapped multiple times around a galvanized or aluminum nail and then each end of the wire connected to a battery for some period of time. What happens when the nail is then positioned next to a paper clip and why

A)the paper clip is repelled away from the nail because an electromagnetic field magnetized the nail . B)the paper clip is attracted toward the nail because an electromagnetic field magnetized the nail . C)no effect at all on the paper clip from the wire or the nail . D)the paper clip straightens out because of Ohm's Law."

Answer:

A)the paper clip is repelled away from the nail because an electromagnetic field magnetized the nail .

Explanation:

An electromagnetic field is a system formed by electric charges where a magnet manifests its action by repelling, or attracting bodies. This system is formed through the passage of an electric current, through conductors, as wires and using an electrical energy source, such as a battery, for example.

As mentioned earlier, this system can establish the attraction or the removal of two bodies. An example of this can be seen in the question above, where a wire is wound several times around a galvanized or aluminum nail and then each end of the wire is connected to a battery for a period of time. If a nail approaches these systems, a magnetized electromagnetic field is created around that nail. The result of this will be that the paper clip will be repelled, as it does not contain attraction poles with the nail.

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In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for
4vir4ik [10]

Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

      k  = 0.903

Explanation:

From the question we are told that

     The time  constant  \tau  =  3

The potential across the capacitor can be mathematically represented as

     V  =  V_o  (1 -  e^{- \tau})

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     V  =  V_o  (1 -  e^{- 3})

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      k  = 0.903

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