Answer:
Tension in the cable is T = 16653.32 N
Explanation:
Give data:
Cross section Area A = 1.3 m^2
Drag coefficient CD = 1.2
Velocity V = 4.3 m/s
Angle made by cable with horizontal =30 degree
Density
Drag force FD is given as
Drag force = 14422.2 N acting opposite to the motion
As cable made angle of 30 degree with horizontal thus horizontal component is take into action to calculate drag force
TCos30 = F_D
T = 16653.32 N
Answer:
14.47 m/s
Explanation:
The momentum must be preserved before and after the collision:
The total momentum before the collision
where are the masses of the car moving south and north, respectively, before the collision.
is the velocity of the car moving South. We take the velocity to the North as the positive direction
The total momentum after the collision
where V = 5.22m/s is the velocity of both cars after the collision
We can equalize the 2 equations and plug in the numbers:
Answer:
angular frequency of the table must be same as the frequency of the projection of the gum on the wall
Explanation:
Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table
So here we will say
so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating
So we can say
so here we can say
so here we can say that
angular frequency of the table must be same as the frequency of the projection of the gum on the wall