Answer:
0.265
Explanation:
Draw a free body diagram. There are four forces:
Normal force Fn pushing up.
Weight force mg pulling down.
Tension force T at an angle θ.
Friction force Fn μ pushing left.
Sum the forces in the y direction:
∑F = ma
Fn + T sin θ − mg = 0
Fn = mg − T sin θ
Sum the forces in the x direction:
∑F = ma
T cos θ − Fn μ = 0
Fn μ = T cos θ
μ = T cos θ / Fn
μ = T cos θ / (mg − T sin θ)
Given T = 164 N, θ = 10.0°, m = 65.0 kg, and g = 9.8 m/s²:
μ = (164 N cos 10.0°) / (65.0 kg × 9.8 m/s² − 164 N sin 10.0°)
μ = 0.265
Answer;
=15855.40 kg/m^3
Explanation;
Volume (V) of the cylinder = pi x r^2 x h
V = 3.14 x (44/2 x 10^-3)^2 x 41.5 x 10^-3
V = 6.307 x 10^-5 m^3
By density = m/V
mass = 1 kg
density = 1/(6.307 x 10^-5) = 15855.40 kg/m^3
Answer:
The equation for the object's displacement is 
Explanation:
Given:
m = 16 lb
δ = 3 in
The stiffness is:
The angular speed is:
The damping force is:
Where
FD = 20 lb
u = 4 ft/s = 48 in/s
Replacing:
The critical damping is equal:
Like cc>c the system is undamped
The equilibrium expression is:
B . light is <span>the physical energy that stimulates sight</span>
The net force on the sledge is 31.64N.
Frictional force = µkR
= 0.269 x 42.2 x 9.81 = 111.36
net force = 143N - 111.36N
= 31.64N
refer brainly.com/question/24557767
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