Question

The square loop shown in the figure moves into a 0.80T magnetic field at a constant speed of 10m/s. The loop has a resistance of 0.10Ω, and it enters the field at t = 0s. Find the induced current in the loop as a function of time. Give your answer as a graph of I versus t from t = 0s to t = 0.020s.

Answer 1

The question ask to find and calculate the induced current in the loop as a function time and the best answer would be that the induced current in the loop is 0.08 amperes. I hope you are satisfied with my answer and feel free to ask for more if you have clarifications and further questions

Answer 2

The induced current in the loop is 20 A

Further explanation

Lenz's law said that when EMF is generated by the change in magnetic flux the polarity of the induced EMF produces an induced current. It induced electric current flows in a direction such that the current opposes the change that induced it

The square loop shown in the figure moves into a 0.80T magnetic field at a constant speed of 10m/s. The loop has a resistance of 0.10Ω, and it enters the field at t = 0s. Find the induced current in the loop as a function of time. Give your answer as a graph of I versus t from t = 0s to t = 0.020s.

B = 0.8 T

L = 5 cm

v = 10 m/s

R = 0.10 Ω

I = ?

∈=E

Ф=o

$I = \frac{E }{R} = \frac{1}{R} |\frac{d o_{m}}{dt} | = \frac{1}{R} \frac{d}{dt} |B.dA|\\I = \frac{1}{R} \frac{d}{dt} |B.dl\Delta s|\\I = \frac{B*l}{R} \frac{ds}{dt} \\I = \frac{B*lv}{R} = \frac{0.80 T*0.05m*50m/s}{0.10 ohm}$

$I = \frac{B*lv}{R} = 20A$

The induced current in the loop is 20 A. According to Lenz's law I goes to counterwise

Learn more

1. Learn more about magnetic field brainly.com/question/9969693
2. Learn more about constant speed brainly.com/question/12427728
3. Learn more       about the induced current brainly.com/question/3712635

Answer details

Grade: 8

Subject:  physics

Chapter:  Lenz's law

Keywords:   magnetic field, constant speed, the induced current, loop, resistance