Answer:
19.98Joules
Explanation:
Energy possessed by the body is the kinetic energy
Kinetic Energy = 1/2mv²
m is the mass
v is the velocity
For the 4kg moving at 6m/s
kE = 1/2 * 4 * 6^2
KE = 1/2 * 4 * 36
KE = 72Joules
For the 4kg moving at 5.1m/s
kE = 1/2 * 4 * 5.1^2
KE = 1/2 * 4 *26.01
KE = 52.02Joules
Amount of Energy lost = 72 - 52.02
Amount of Energy lost = 19.98Joules
Hence the amount of Energy lost is 19.98Joules
That's the description of the SOLID phase of matter.
Answer:
<em>Net force = 21.12 N</em>
<em>angle for the force α = 45°</em>
Explanation:
<em>In this problem, we will take the left as the negative x-axis, the right as the positive x-axis, and the upward direction as the positive y-axis.</em>
The 20 N force to the left has an x component of -20 N, and y component of 0 N
The 35 N force to the right has a x component of 35 N, and a y component of 0 N
The 15 N upwards has an x component of 0 N, and a y component of 15 N
We resolve the forces into the x and y components.
for the x component Fx
Fx = -20 + 35 + 0 = 15 N
For the y component Fy
Fy = 0 + 0 + 15 = 15 N
Net force Fn = 
<em>Net force Fn = 21.21 N</em>
for the angle,
α = 
1
<em>angle for force α = 45°</em>
Answer:
P' = 4 P
Therefore, the power dissipated by the circuit will becomes four times of its initial value.
Explanation:
The power dissipation by an electrical circuit is given by the following formula:
Power Dissipation = (Voltage)(Current)
P = VI
but, from Ohm's Law, we know that:
Voltage = (Current)(Resistance)
V = IR
Substituting this in formula of power:
P = (IR)(I)
P = I²R ---------------- equation 1
Now, if we double the current , then the power dissipated by that circuit will be:
P' = I'²R
where,
I' = 2 I
Therefore,
P' = (2 I)²R
P' = 4 I²R
using equation 1
<u>P' = 4 P</u>
<u>Therefore, the power dissipated by the circuit will becomes four times of its initial value.</u>
Copper conducts electricity
