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Pavlova-9 [17]
2 years ago
9

Here's a question from ~ [ AIEEE 2002 ]

Physics
2 answers:
Andrew [12]2 years ago
8 0

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

The given parameters:

  • <em>Radius of the curve, r = 150 m</em>
  • <em>Coefficient of friction, μ = 0.6</em>

<em />

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is calculated as follows;

\frac{mv^2}{r} = \mu mg\\\\v^2 = \frac{\mu mgr}{m} \\\\v^2 = \mu gr\\\\v = \sqrt{\mu gr} \\\\v = \sqrt{0.6 \times 9.8 \times 150} \\\\v = 29.7 \ m/s

Thus, the minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

Learn more about banked roads here: brainly.com/question/14777525

lyudmila [28]2 years ago
7 0
  • r=150m
  • coefficient of friction=\mu=0.6

As car is avoid skidding

\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg

  • Cancel m

\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g

\\ \sf\hookrightarrow v^2=\mu rg

\\ \sf\hookrightarrow v^2=0.6(10)(150)

\\ \sf\hookrightarrow v^2=60(150)

\\ \sf\hookrightarrow v^2=900

\\ \sf\hookrightarrow v=30ms^{-1}

Done

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