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solniwko [45]
2 years ago
5

Waves travel as "packets" of several waves. in these "packets," a wave travels at __________.

Physics
2 answers:
dalvyx [7]2 years ago
8 0

Answer:

a. the same speed as the wave energy

Explanation:

Wave packet is only an envelope of a more localized wave. The entire wave is a combination of the discrete wave packets.

Wave is any disturbance that travels across space. A wave does not carry the particles of the medium in which travels. It carries energy from one point to another  as it travels.

For an electromagnetic wave, the energy of the wave is due to the vibrations of the electric and magnetic fields of the wave. For sound waves, wave energy is the vibrations or disturbance of the particles of the medium in which the sound wave travels.

madam [21]2 years ago
4 0
A. the same speed as the wave energy 
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A beetle with a mass of 15.0 g is initially at rest on the outer edge of a horizontal turntable that is also initially at rest.
vichka [17]

Answer:

- 8.33 x 10⁻³ rad /s ( anticlockwise)

Explanation:

The rotational movement of beetle and turntable is caused by torque generated by internal forces , we can apply conservation of  angular momentum.

That is ,

I₁ ω₁ = I₂ω₂ ,   ω₁ and ω₂ are angular velocity of beetle and turntable respectively.

ω₁ + ω₂ = .05 radian /s ( given )

Momentum of inertia of beetle I₁ = mass x (distance from axis)²

= 15 x 10⁻³ x R² ( R is radius of the turntable )

Momentum of inertia of turntable  I₂ =1/2 mass x (distance from axis)²

= 75/2 x 10⁻³ x R² ( R is radius of the turntable )

I₁ ω₁ = I₂ω₂ ,

15 x 10⁻³ x R² x ( .05 -  ω₂ ) = 75/2 x 10⁻³ x R² ω₂

15 x  ( .05 -  ω₂ ) = 75/2 x  ω₂

.75 - 15ω₂ = 37.5ω₂

.75 = 52.5  ω₂

ω₂ = - 14.3  x 10⁻³ rad /s ( anticlockwise)

7 0
2 years ago
A girl pushes on a table with a 5-newton force directed to the east. Her friend pushes on the same table with a 10- newton force
nalin [4]

Think like this: 10 is twice as much as 5.

Answer A pushes 2 squares east and 4 squares sout, being doubled just as 10 is to 5. Happy to help :)

4 0
2 years ago
Read 2 more answers
Compare and contrast lava and magma
earnstyle [38]
Magma<span> is made up of molten rock, and it is stored in Earth's crust. </span><span> When the volcano erupts, magma flows out of the volcano, it is usually mixed with steam and gas, which is called lava.</span>
4 0
3 years ago
The lowest possible temperature in outer space is 3.13 K. What is the rms speed of hydrogen molecules at this temperature? (The
Umnica [9.8K]

Answer:

v_{rms} =196.59 m/s

Given:

Temperature, T = 3.13 K

molar mass of molecular hydrogen, m = 2.02 g/mol = 2.02\times 10^{-3}kg/mol

Solution:

To calculate the root mean squarer or rms speed of hydrogen molecule, we use the given formula:

v_{rms} = \sqrt{\frac{3TR}{m}}

where

R = rydberg's constant = 8.314 J/mol-K

Putting the values in the above formula:

v_{rms} = \sqrt{\frac{3\times 3.13\times 8.314}{2.02\times 10^{-3}}}

v_{rms} =196.59 m/s

5 0
3 years ago
You are an engineer helping to design a roller coaster that carries passengers down a steep track and around a vertical loop. Th
vova2212 [387]

Answer:

h >5/2r

Explanation:

This problem involves the application of the concepts of force and the work-energy theorem.

The roller coaster undergoes circular motion when going round the loop. For the rider to stay in contact with the cart at all times, the roller coaster must be moving with a minimum velocity v such that at the top the rider is in a uniform circular motion and does not fall out of the cart. The rider moves around the circle with an acceleration a = v²/r. Where r = radius of the circle.

Vertically two forces are acting on the rider, the weight and normal force of the cart on the rider. The normal force and weight are acting downwards at the top. For the rider not to fall out of the cart at the top, the normal force on the rider must be zero. This brings in a design requirement for the roller coaster to move at a minimum speed such that the cart exerts no force on the rider. This speed occurs when the normal force acting on the rider is zero (only the weight of the rider is acting on the rider)

So from newton's second law of motion,

W – N = mv²/r

N = normal force = 0

W = mg

mg = ma = mv²/r

mg = mv²/r

v²= rg

v = √(rg)

The roller coaster starts from height h. Its potential energy changes as it travels on its course. The potential energy decreases from a value mgh at the height h to mg×2r at the top of the loop. No other force is acting on the roller coaster except the force of gravity which is a conservative force so, energy is conserved. Because energy is conserved the total change in the potential energy of the rider must be at least equal to or greater than the kinetic energy of the rider at the top of the loop

So

ΔPE = ΔKE = 1/2mv²

The height at the roller coaster starts is usually higher than the top of the loop by design. So

ΔPE =mgh - mg×2r = mg(h – 2r)

2r is the vertical distance from the base of the loop to the top of the loop, basically the diameter of the loop.

In order for the roller coaster to move smoothly and not come to a halt at the top of the loop, the ΔPE must be greater than the ΔKE at the top.

So ΔPE > ΔKE at the top. The extra energy moves the rider the loop from the top.

ΔPE > ΔKE

mg(h–2r) > 1/2mv²

g(h–2r) > 1/2(√(rg))²

g(h–2r) > 1/2×rg

h–2r > 1/2×r

h > 2r + 1/2r

h > 5/2r

5 0
3 years ago
Read 2 more answers
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