Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.
The distance of the earth from the sun is
.
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What is Kepler's third law?</h3>
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.
By using Kepler's third law, this can be written as,


Substituting the values, we get the value of constant k for mars.


The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.



Hence we can conclude that the distance of the earth from the sun is
.
To know more about Kepler's third law, follow the link given below.
brainly.com/question/7783290.
That is false I think sorry if its not correct
Answer:
50.96 N
Explanation:
weight = mass x gravity
We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.
w = m x g
w = 5.2 kg x 9.8 m/s^2
w = 50.96 N
The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!
Answer:
There is 2 beats per second.
Explanation:
You have to subtract them to find your answer and 178 - 176= 2
Answer:

Explanation:
Given that,
The half-life of Barium-139 is 
A sample contains
nuclei.
We need to find the decay constant for this decay. The formula for half life is given by :

Put all the values,

So, the decay constant is
.