Answer: Sublimation I think.
Explanation:
Answer:
(a) 0.525
(b) 1750J
Explanation:
Coefficient of Performance (COP) = Q2/(Q1 - Q2)
Q1 = heat rejected to the surrounding = 1750J
Q2 = heat absorbed in the environment = 585K
COP = 585/(1700 - 585) = 585/1115 = 0.525
(b). Heat expelled to the surrounding (room) = 1750J
Answer:
5.4 × 10⁸ W/m²
Explanation:
Given that:
The Power (P) of Betelgeuse is estimated to release 3.846 × 10³¹ W
the mass of the exoplanet = 5.972 × 10²⁴ kg
radius of the earth = 1.27 × 10⁷ m
half the distance (i.e radius r ) = 7.5 × 10¹⁰ m
a) What is the intensity of Betelgeuse at the "earth’s" surface?
The Intensity of Betelgeuse can be determined by using the formula:


I = 544097698.8 W/m²
I = 5.4 × 10⁸ W/m²
Answer:
the answer should be a constant
hope this helps!!