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Bond [772]
3 years ago
15

The distance, in feet, a moving object has traveled after t seconds is given by 2t/(4 + t). find the acceleration of the object

after 5 seconds. (round your answer to three decimal places.)
Physics
1 answer:
lianna [129]3 years ago
3 0
Hi! Let me help you!
a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0 
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
a = 2/9 ft/s^2 <---- Answer
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