The distance, in feet, a moving object has traveled after t seconds is given by 2t/(4 + t). find the acceleration of the object
1 answer:
You might be interested in
At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.
We have a circular loop of radius ' r ' carrying current ' i '.
We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.
<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -
Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -
Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -
r = 0.766R
Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.
To solve more questions on magnetic field intensity, visit the link below-
#SPJ4
Explanation:
We know that kWh is a commercial unit of energy.
Also, 1 Joule = 1 watt × 1 seconds
Since ,1 h = 3600 s and 1kW = 1000 W
So, the relation is :
1 watt is defined as the power of an appliance when the energy is transferred at a rate of 1 Joule per second.