3 years ago

A hockey ball accelerates from 0.m/s to 25m/s in 0.05 seconds what is the acceleration of the ball ?

Physics

1 answer:

S_A_V [24]3 years ago

3 0

Answer:

500

Explanation:

25/0.05 .

I think this ?

You might be interested in

You can also describe position by using coordinates of _____and _______

SOVA2 [1]

Answer:

x and y

Explanation:

7 0

3 years ago

37 Questions - All Questions Are Required

ANTONII [103]

Acceleration = vf-vi /t
10-22/3=2.6m/s^2

5 0

3 years ago

Read 2 more answers

What is kinematics ?? xD -,- xD

lorasvet [3.4K]

Answer:

Kinematics is a <em>subfield of physics, developed in classical mechanics, that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the forces that cause them to move.</em>

Explanation:

Hope this helps!

Blazetoxic123

7 0

3 years ago

Anyone knows this please help me

olasank [31]

Answer:

TRUE

Explanation:

3 0

3 years ago

Read 2 more answers

When an excited electron falls from n = 3 to n = 2, a red radiation in the Balmer series emitted. What is the frequency of this

vichka [17]

Answer:

The frequency of this photon is $4.57\times10^{14}\ Hz$

(D) is correct option.

Explanation:

Given that,

Excited states,

$n=3$

$n=2$

We need to calculate the wavelength

Using formula for energy

$E=13.6(\dfrac{1}{n^2}-\dfrac{1}{m^2})$

$E=13.6(\dfrac{1}{4}-\dfrac{1}{9})$

$E=1.888\ eV$

$E=1.888\times1.6\times10^{-19}\ J$

$E=3.0208\times10^{-19}\ J$

We need to calculate the frequency

Using formula of frequency

$E=hf$

$f=\dfrac{E}{h}$

Where, E =energy

$f=\dfrac{3.0208\times10^{-19}}{6.63\times10^{-34}}$

$f=4.57\times10^{14}\ Hz$

Hence, The frequency of this photon is $4.57\times10^{14}\ Hz$

4 0

3 years ago