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3 years ago

10

A certain microwave has a

1 answer:

Tatiana [17]3 years ago

5 0

Answer:

$9.375\times 10^{9} Hz$

Explanation:

Frequency is mathematically defined as the quotient of speed divided by wavelength.

$Frequency= \frac {v}{W}$

where

v-is the speed of light

-w is wavelength.

Given the speed of the wave as $V=300000000 \ m/s$ and the wavelength $\lambda= 0.032\ m$ , we substitute these values in the Frequency function to solve for frequency:

$Frequency=\frac {300000000}{0.032}=9375000000 Hz=9.375\times 10^{9} Hz$

Hence, the wave's frequency is $9.375\times 10^9\ Hz$

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Dumbo the elephant weights 13,000 pounds. What force would the Earths surface apply to Dumbo? 2.2 pounds = 1 kg

snow_lady [41]

Answer:

57908 N

Explanation:

Let's first convert Dumbo's mass into kg using the given relationship: 2.2 pounds =1 kg.

Then, 13000 lbs = 13000/2.2 kg = 5909 kg

Now, let's find the force of gravity on Dumbo at the surface of the earth, which would be in magnitude equal to the normal force that the Earth's surface applies on Dumbo.

F = m * a = 5909 kg * 9.8 m/s^2 = 57908 N

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3 years ago

How did Galileo increase public support for Copernicus’s model?

miskamm [114]

I think by using data collected by Tycho Brahe

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3 years ago

Read 2 more answers

Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generate

tigry1 [53]

Explanation:

It is given that,

Average power per unit mass generated by Lance, $\dfrac{P}{m}=6.5\ W/kg$

$P=6.5\times 75=487.5\ W$

(a) Distance to cover race, $d = 160\ km =160\times 10^3\ m$

Average speed of the person, v = 11 m/s

If t is the time taken to cover the race.

$t=\dfrac{d}{v}$

$t=\dfrac{160\times 10^3\ m}{11\ m/s}$

t = 14545.46 s

Let W is the work done. The relation between the work done and the power is given by :

$P=\dfrac{W}{t}$

$W=P\times t$

$W=487.5\times 14545.46$

W = 7090911.75 J

(b) Since, $1\ J=2.389\times 10^{-4}\ calories$

So, in 7090911.75 J, $W=7090911.75 \times 2.389\times 10^{-4}$

W = 1694.01 J

Hence, this is the required solution.

6 0

3 years ago

A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note

shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

The ball is thrown straight upward with initial velocity u

The ball reaches a maximum height of 4.5 m

At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is <em>v² = u² + 2ah</em>, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

⇒ 0 = u² - 88.2

Add 88.2 to both sides

⇒ 88.2 = u²

Take square root for both sides

⇒ u = 9.39 m/s

<em>The initial velocity was 9.39 m/s</em>

5 0

3 years ago

The 88-lb force P is applied to the 210-lb crate, which is stationary before the force is applied. Determine the magnitude and d

Marina86 [1]

Answer:

$F=-88Ib$

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

$Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)$

$F=u*N$

with $\mu =0.47$

$F=98.7Ib$

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

$F=-88Ib$

5 0

3 years ago