All categories

2 years ago

A kind of tempory magnet

Physics

2 answers:

netineya [11]2 years ago

8 0

Answer:

Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

Explanation:

Alecsey [184]2 years ago

6 0

Answer:

nails and paperclips

Explanation: Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

You might be interested in

An Olympic swimmer swims 50.0 meters in 23.1 seconds . What is his average speed

Aneli [31]

If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.

So his average speed is 2.16 m/s.

3 0

2 years ago

How long does it take the students’ kettle to come to the boil if 3 kg of ice at 0 °C is put in it? The latent heat of fusion of

Alborosie

Answer:

Explanation:

111.333

3 0

2 years ago

Three long parallel wires each carry 2.0-A currents in the same direction. The wires are oriented vertically, and they pass thro

blagie [28]

Answer:

$21.2\times 10^{-6}$ T

Explanation:

$i$ = magnitude of current in each wire = 2.0 A

$a$ = length of the side of the square = 4 cm = 0.04 m

$r$ = length of the diagonal of the square = $\sqrt{2}$ a = $\sqrt{2}$ (0.04) = 0.057 m

$B$ = magnitude of magnetic field by wires at A and C

$B = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{a} \right )$

$B = (10^{-7}) \left ( \frac{2(2)}{0.04} \right )$

$B = 10\times 10^{-6}$ T

$B'$ = magnitude of magnetic field by wire at B

$B' = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{r} \right )$

$B' = (10^{-7}) \left ( \frac{2(2)}{0.057} \right )$

$B' = 7.02\times 10^{-6}$ T

Net magnitude of the magnetic field at D is given as

$B_{net} = \sqrt{B^{2}+B^{2}} + B'$

$B_{net} = \sqrt{2} B + B'$

$B_{net} = \sqrt{2} (10\times 10^{-6}) + (7.02\times 10^{-6})$

$B_{net} = 21.2\times 10^{-6}$ T

8 0

2 years ago

BRAINLIEST

In-s [12.5K]

Answer:

Explanation:

1) acceleration is the change in velocity of a body with respect to time.

acceleration = velocity/time

Given

velocity = 139m/s

time = 20secs

acceleration = 139/20

acceleration = 6.95m/s²

Hence its average acceleration during the first 20 seconds of the launch is 6.95m/s²

2) Speed is the rate of change of distance with respect to time.

average speed = distance/time

Time = distance/speed

Time = 100/7823

Time = 0.013s

3) Using the equation of motion v² = u²+2as

v² = 0²+2(15)(60)

v² = 30*60

v² =1800

v = √1800

v = 42.43m/s

7 0

2 years ago

What is the most appropriate tool to use when collecting data from the investigation

NeTakaya

If it is just a reseach investigatory project, you could monitor it by using different variables (controlled), acurate measuring devices and camera for documentations

7 0

2 years ago

A kind of tempory magnet​

A kind of tempory magnet