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pishuonlain [190]

3 years ago

7

A kind of tempory magnet

2 answers:

netineya [11]3 years ago

8 0

Answer:

Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

Explanation:

Alecsey [184]3 years ago

6 0

Answer:

nails and paperclips

Explanation: Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

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How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.

-BARSIC- [3]

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance = 6.34 x 10⁴mm

Unknown:

Time = ?

Solution:

Power is the rate at which work is done;

Mathematically;

Power = $\frac{work done}{time}$

Time = $\frac{work done}{power}$

Work done = weight x height

convert mass to kg;

100g = 1kg;

1.47 x 10⁴g = 14.7kg

convert the height to m;

1000mm = 1m

6.34 x 10⁴mm gives 63.4m

Work done = 14.7 x 9.8 x 63.4 = 9133.4J

Time taken = $\frac{9133.4}{2190}$ = 4.2s

6 0

3 years ago

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spin [16.1K]

A=f/m
A=900/425
A=2.18

To determine acceleration you divide the force by the mass.

4 0

2 years ago

Read 2 more answers

You are presently taking a weather observation. The sky is full of wispy cirrus clouds estimated to be about 10 km overhead. If

marshall27 [118]

Answer:

x = 2000 Km

Explanation:

Given

y = 10 km

Slope: 1 : 200

x = ?

We can apply the formula

y / x = 1 / 200 ⇒ x = 200*y = 200*10 Km

⇒ x = 2000 Km

7 0

3 years ago

Branches of sicence

Sonja [21]

Answer:

physical science

earth science and life science

5 0

3 years ago

Read 2 more answers

A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d

cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

$\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg$

$Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}$

(b) By substituting the values

$Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}$

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0

4 years ago