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pishuonlain [190]
4 years ago
7

A kind of tempory magnet​

Physics
2 answers:
netineya [11]4 years ago
8 0

Answer:

Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

Explanation:

Alecsey [184]4 years ago
6 0

Answer:

nails and paperclips

Explanation: Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

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What is a Ramjet engine?
nadezda [96]
Hi,

A Ramjet engine is a type of jet engine. There are four kinds of jet engines: <span>Rocket Jet, Ramjet, Pulsejet, and Turbine Jet.

By definition, a Ramjet engine is </span><span>a type of jet engine in which the air drawn in for combustion is compressed solely by the forward motion of the aircraft.


Faith xoxo</span>
8 0
4 years ago
What is the change in momentum of a ball if a force of 5.0 N acts on it for a brief time of 4 ms?
Gnoma [55]

Answer:

0.02 Ns

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Time (t) = 4 ms

Change in momentum =?

Next, we shall convert 4 ms to s. This can be obtained as follow:

1 ms = 1×10¯³ s

Therefore,

4 ms = 4 ms × 1×10¯³ s / 1 ms

4 ms = 4×10¯³ s

Thus, 4 ms is equivalent to 4×10¯³ s

Change in momentum = Impulse

Impulse (I) = Force (F) × time (t)

Change in momentum = Force (F) × time (t)

Force (F) = 5 N

Time (t) = 4×10¯³ s

Change in momentum =?

Change in momentum = 5 × 4×10¯³

Change in momentum = 0.02 Ns

Therefore, the change in the momentum of the ball is 0.02 Ns.

4 0
3 years ago
A fathom is a unit of length, usually reserved for measuring the depth of water. A fathom is exactly 6.00 ft in length. Take the
iragen [17]

Answer:

216480000 fathoms

Explanation:

1 fathom = 6 feet

1\ feet=\frac{1}{6}\ fathom

Distance from Earth to the Moon = 246000 miles

Converting to feet

1 mile = 5280 feet

246000 miles = 1298880000 feet

Convert to fathom

1\ feet=\frac{1}{6}\ fathom\\\Rightarrow 1298880000\ feet=\frac{1298880000}{6}=216480000\ fathom

So, the distance between Earth and Moon is 216480000 fathoms

7 0
3 years ago
A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. The d
-BARSIC- [3]

Answer:

a) t=6.37s

b) t=3.3333s

Explanation:

The knowable variables are the initial hight and initial velocity

s_{o}=80ft

v_{os}=64ft/s

The equation that describes the motion of the ball is:

s=80+64t-16t^{2}

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

0=80+64t-12t^{2}

a) Solving for t, we are going to have two answers

t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a=-16

b=64

c=80

t=-1.045 s or t=6.378s

<em><u>Since time can not be negative the answer is t=6.378s </u></em>

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

v_{y}=v_{o}+gt

at maximum point the velocity is 0

0=64-32.2t

Solving for t

t=1.9875 s

Now, we must know how much distance does it take to reach maximum point

s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft

So, the ball pass the top of the building on its way down at 160 ft

160=80+64t-16t^{2}

Solving for t

t=2s or t=3.333s

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

4 0
3 years ago
Read 2 more answers
A 60 kg swimmer at a water park enters a pool using a 2 m high slide. Find the velocity of the swimmer
koban [17]

Answer:

the velocity of the swimmer at the bottom of the slide is 6.26 m/s

Explanation:

The computation of the velocity of the swimmer at the bottom of the slide is given below:

v = √2gh

= √2 × 9.8 × 2

= 6.26 m/s

Hence, the velocity of the swimmer at the bottom of the slide is 6.26 m/s

5 0
3 years ago
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