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Alexandra [31]
3 years ago
14

Based on the trend in valence electrons across periods for main-group

Physics
2 answers:
Andreyy893 years ago
6 0

Answer: 4

Explanation: a p e x

Sergeeva-Olga [200]3 years ago
4 0

Answer: 4

Explanation:

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A single conservative force acts on a 4.50-kg particle within a system due to its interaction with the rest of the system. The e
den301095 [7]

Answer: (a) The work done by this force on the particle is 42.71 J.

(b) The change in the potential energy of the system is -42.71 J.

(c) The kinetic energy the particle is 62.96 J.

Explanation:

(a)  For the given situation, expression for work done is as follows.

           W = \int_{0.9}^{5.15}Fdx

               = \int_{0.9}^{5.15}(2x + 4)dx

               = [2\frac{x^{2}}{2} + 4x]^{5.15}_{0.9}

               = (x^{2} + 4x)^{5.15}_{0.9}

               = [(5.15)^{2} + 4(5.15) - (0.9)^{2} - 4(0.9)]

               = 26.52 + 20.6 - 0.81 - 3.6

               = 42.71 J

Hence, the work done by this force on the particle is 42.71 J.

(b)  Expression for a conservative force is as follows.

              F = -\frac{dU}{dx}

            dU = -Fdx

      \int_{0.9}^{5.15}dU =  \int_{0.9}^{5.15}Fdx

        \int_{0.9}^{5.15}dU = -42.71 J

Therefore, the change in the potential energy of the system is -42.71 J.

(c) According to the work energy theorem,

         W = \Delta K.E

     K.E_{0.9} - K.E_{5.15} = W

            K.E_{0.9} = W + K.E_{5.15}

                          = 42.71 + \frac{1}{2}mu^{2}  

where, u = velocity of the mass at x = 0.9 m

         u = 3.0 m/s,       m = 4.50 kg

As,   K.E_{0.9} = W + K.E_{5.15}

                   = 42.71 + \frac{1}{2} \times 4.50 \times (3)^{2}

                   = 62.96 J

Therefore, the kinetic energy the particle is 62.96 J.

8 0
3 years ago
Help please :((((
snow_tiger [21]

Answer:

Hamid

Explanation:

I got it right on my test

6 0
2 years ago
run at the same speed and in the same direction, and they both run for the same amount of time, what can you say about the dista
LenaWriter [7]

Answer:

the are equivalent

Explanation:

i just learned about that

4 0
4 years ago
Which of the following equations illustrates the law of conservation of<br> matter?
vagabundo [1.1K]

Answer:

I see no eaquations?

It should be matter=constant

3 0
3 years ago
a 3 kg piece of putty that is moving with a velocity of 10 m/s collides and sticks to an 8 kg bowling ball that was at rest. wha
defon

The final velocity is 2.7 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the system must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 3 kg is the mass of the putty

u_1 = 10 m/s is the initial velocity of the putty (we take its direction as positive direction)

m_2 = 8 kg is the mass of the ball

u_2 = 0 m/s is the initial velocity of the ball (at rest)

v is the final combined velocity of the two putty+ball

Re-arranging the equation and substituting the values, we find the  final combined velocity:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(3)(10)+0}{3+8}=2.7 m/s

And the positive sign indicates their final direction is the same as the initial direction of the putty.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

3 0
3 years ago
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