Answer: (a) The work done by this force on the particle is 42.71 J.
(b) The change in the potential energy of the system is -42.71 J.
(c) The kinetic energy the particle is 62.96 J.
Explanation:
(a) For the given situation, expression for work done is as follows.
W = 
= 
= ![[2\frac{x^{2}}{2} + 4x]^{5.15}_{0.9}](https://tex.z-dn.net/?f=%5B2%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%20%2B%204x%5D%5E%7B5.15%7D_%7B0.9%7D)
= 
= ![[(5.15)^{2} + 4(5.15) - (0.9)^{2} - 4(0.9)]](https://tex.z-dn.net/?f=%5B%285.15%29%5E%7B2%7D%20%2B%204%285.15%29%20-%20%280.9%29%5E%7B2%7D%20-%204%280.9%29%5D)
= 26.52 + 20.6 - 0.81 - 3.6
= 42.71 J
Hence, the work done by this force on the particle is 42.71 J.
(b) Expression for a conservative force is as follows.
F = 
dU = -Fdx
= 
= -42.71 J
Therefore, the change in the potential energy of the system is -42.71 J.
(c) According to the work energy theorem,
W = 
= W

=
where, u = velocity of the mass at x = 0.9 m
u = 3.0 m/s, m = 4.50 kg
As, 
= 
= 62.96 J
Therefore, the kinetic energy the particle is 62.96 J.
Answer:
Hamid
Explanation:
I got it right on my test
Answer:
the are equivalent
Explanation:
i just learned about that
Answer:
I see no eaquations?
It should be matter=constant
The final velocity is 2.7 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the system must be conserved before and after the collision.
Therefore we can write:
where:
is the mass of the putty
is the initial velocity of the putty (we take its direction as positive direction)
is the mass of the ball
is the initial velocity of the ball (at rest)
is the final combined velocity of the two putty+ball
Re-arranging the equation and substituting the values, we find the final combined velocity:
And the positive sign indicates their final direction is the same as the initial direction of the putty.
Learn more about momentum here:
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