Question

You use 10.0 mL of solution A, 10.0 mL of solution B, and 70.0 mL of water for your first mixture. What is the initial concentration of KIO3

Answer 1

Complete Question

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Answer:

The  initial concentration is  $C_f = 0.0022 \ M$

Explanation:

From the question we are told that

    The volume of solution A is  $V_i = 10.0 mL$

    The concentration of A is $C_i = 0.0200 \ M$

    The volume of solution B  is  $V_B = 10.0mL$

    The volume of water is  $V_{w } = 70.0 mL$

Generally the law of dilution is mathematically represented as

             $C_i * V_i = C_f * V_f$

Where  $C_f$ is the concentration of  the mixture

            $V_f$ is the volume of the mixture which is mathematically evaluated as

            $V_f = 10 + 10 + 70$

           $V_f = 90mL$

So  

      $C_f = \frac{C_i * V_i}{ V_f}$

substituting values

       $C_f = \frac{0.0200 * 10 }{90}$

       $C_f = 0.0022 \ M$

Note the mixture obtained is  $KIO_3$