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allochka39001 [22]
3 years ago
15

PLEASE HELP ME 20 POINTS!!!!!

Chemistry
1 answer:
julsineya [31]3 years ago
5 0

Answer:

Theoretical yield of the reaction is 121·38 g

The excess reactant is hydrogen

The limiting reactant is nitrogen

Explanation:

By assuming that the reaction between nitrogen and hydrogen taking place in presence of catalyst because at normal conditions the reaction between them will not occur

Number of moles of nitrogen taken are 100÷28 ≈ 3.57

Number of moles of hydrogen taken are 100÷2 = 50

Actually the reaction between nitrogen and hydrogen takes place according to the following equation

<h3>Nx_{2} + 3Hx_{2}  → 2NHx_{3}</h3>

So from the equation for 1  mole of nitrogen and 3 moles of hydrogen we get 2 moles of ammonia

Here in the problem we have approximately 3·57 moles of nitrogen so we require 3×3·57 moles of hydrogen

∴ Number of moles of hydrogen required is 10·71

But we have 50 moles of hydrogen

∴ Excess reagent is hydrogen and limiting reagent is nitrogen

Number of moles of ammonia produced  is 2×3·57 = 7·14

Weight of ammonia is 17 g

∴ Amount of ammonia produced is 17×7·14 = 121·38 g

∴ Theoretical yield of the reaction is 121·38 g

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Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.

Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)

How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?

Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

g Sn → mol Sn → mol HF

Step 2: Solve.

75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF

Step 3: Think about your result.

The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
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2 years ago
Read 2 more answers
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