Answer:
The line drawn through points D and E.
Explanation:
Y is a horizontal line and D and E are both on the same line. If a line were drawn it would be within the Y plane.
<h3>
Answer:</h3>
4.227 × 10^-19 Joules
<h3>
Explanation:</h3>
Energy of a photon of light is calculated by the formula;
E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.
But, f = c/λ
Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.
Given the wavelength is 470 nm or 4.7 × 10^-7 m
Therefore;
E = hc/λ
= (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m
= 4.227 × 10^-19 Joules
Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules
Answer:
3
Explanation:
Lt= Loe^(-kt)
Data:
Lo = 10 mg/mL
Assume k = 0.23/da
1. Calculate L5
L5 = 10e^(-5×0.23) = 10e^-1.15 = 10 × 0.317 = 3.17 mg/mL
2. Calculate the dilution factor
You expect to find L5 to be about 3
You want L5 to be about 1.
You should use a dilute your sample by a factor of 3.
P = 3
Answer:
Option (3) 334J.
Explanation:
The following data were obtained from the question:
Mass (m) = 1g
Heat of fusion (ΔHf) = 334J/g
Heat (Q) =?
The heat released can be obtained as follow:
Q = m·ΔHf
Q = 1 x 334
Q = 334J.
Therefore, the heat released when 1g is converted to ice is 334J.
The answer is (4) neutron and proton. The electron has very little mass and the neutron and proton have approximately the same mass. The positron has approximately the same mass as electron. The beta particle is electron. And the alpha particle is the nucleus of He which is about the same mass as 4 protons.
