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weqwewe [10]
3 years ago
11

True or false. (Pls help)

Chemistry
2 answers:
NNADVOKAT [17]3 years ago
6 0

Answer:

1.) False?

2.) true. sorry english not my first language

grigory [225]3 years ago
5 0
I believe they’re both true.
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Aneli [31]

Answer:

Explanation:

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2 years ago
At what temperature does uranium hexafluoride have a density of 0.9560 g/L at 0.5073 atm?
S_A_V [24]
Given:



Density = 0.7360 g/L.

Pressure = 0.5073 atm.
Step 2
The mathematical expression of an ideal gas is,

Chemistry homework question answer, step 2, image 1
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8 0
4 years ago
The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

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R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

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Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
In which group of the Periodic Table do most of the elements exhibit both positive and negative oxidation states?
Shtirlitz [24]
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4 0
3 years ago
MgCl2 + AgNO3 → AgCl + Mg(NO3)2
Law Incorporation [45]

Answer:

MgCl2 + 2AgNO3 → 2AgCl + Mg(NO3)2

Explanation:

I'm assuming you want to balance it so...

The first thing I see is that there are two chlorines on the reactant side and one on the product side

Adding a coefficient of 2 would get 2AgCl2

Now there are two silvers on the reactant side, so add a 2 to AgNO3 on the products side. Now they are all balanced.

If that is not what you are looking for let me know!

6 0
3 years ago
Read 2 more answers
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