<span>5.506x10^23 atoms
First, determine the molar mass of Calcium Nitrate [ Ca(NO3)2 ]. Look up the atomic weights of the involved elements.
Atomic weight calcium = 40.078
Atomic weight nitrogen = 14.0067
Atomic weight oxygen = 15.999
Molar mass Ca(NO3)2 = 40.078 + 2 * 14.0067 + 6 * 15.999 = 164.0854 g/mol
Determine the number of moles of Ca(NO3)2.
16.67 g / 164.0854 g/mol = 0.101593439 mol
Now multiply by the number of atoms in Ca(NO3)2 which is 9. So
9 * 0.101593439 = 0.914340947
Finally, multiply by avogadro's number. Giving:
0.914340947 * 6.0221409x10^23 = 5.50629001x10^23
Round the result to 4 significant figures, giving 5.506x10^23 atoms.</span>
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