Answer: The picture shows the elliptical galaxy.
Explanation :
There are three types of galaxies i.e.
The given picture shows an elliptical galaxy. It has a shape of the spheroid or elongated sphere. As we go farther away from the center, the brightness goes on decreasing.
Hence, the correct option is (c) " elliptical galaxy ".
<span>The first thing you need to consider all the displacements in y direction.
S1 has no displacement in y direction.
S2 has a displacement of (-210 sin 45)
S3 has a displacement of (270 sin30)
but
S1 + S2+ S3+ S4 = 0
0 + (-210 sin 45) + (270 sin30) + Sy=0
Sy= +105 *sqrt2 - 135 = 148.05 -135 = 13.05
You need to consider also the displacement in x direction
S1 has a displacement of -190 m
S2 has a displacement of 210 cos45
S3 has a displacement of 270 cos 30
S1 + S2 + S3 + S4 = 0
-190 + 105 * sqrt2 + 135* sqrt3 +S4 = 0
S4 =190 - 148.05 - 233.55= - 191.6
Final displacement would be the result of 191.6i - 13.05j
I hope this can help</span>
Answer:
See the explanation below.
Explanation:
Resistance C is connected in parallel with the 120 V voltage source, so we can determine the current through this resistance by the ohm law.
I = V / R
where:
V = voltage [volt]
R = resistance [ohm]
I = 120 / 100
I = 1.2[amp]
The resistors d, e & f, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.
Rt = 400 + 200 + 200 = 800 [ohm]
This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.
I2 = 120 / 800 = 0.15 [amp]
The resistors a & b, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.
Rt2 = 100 + 100 = 200 [ohm]
This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.
I3 = 120 / 200 = 0.6 [amp]
Now we can write the currents for each of the resistors.
a ) I = 0.6 [amp]
b) I = 0.6 [amp]
c) I = 1.2 [amp]
d) I = 0.15 [amp]
e) I = 0.15 [amp]
f) I = 0.15 [amp]
Answer:
Convex lenses concentrates the light energy to one spot on the paper so that the heat energy accumulates on that one small spot of paper. ... As the heat increases, combustion will occur when the spot becomes too hot and the paper will burn.
Explanation:
Hope it helps!
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Answer: 7840 joules
Explanation:
Given that:
Potential energy of rock = ?
Mass of rock = 20 kg
Height = 40 metres
Acceleration due to gravity g = 9.8m/s2
Recall that potential energy (P.E) is the energy possessed by an object at rest. So, for the rock at rest:
P.E = Mass x Acceleration due to gravity x height
= 20 kg x 9.8m/s2 x 40 metres
= 7840 joules
Thus, the potential energy of the rock is
7840 joules
