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astraxan [27]
3 years ago
8

Which energy source is formed when organic matter is trapped underground without exposure to air or moisture?

Physics
2 answers:
REY [17]3 years ago
8 0
C. Coal Is The Answer

mars1129 [50]3 years ago
5 0

coal is the correct answer

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What exerts a centripetal force on a person running around a curve?
Eduardwww [97]

Answer:

The inertial force of the body

Explanation:

Everybody that is moving in a curved path has an inertial force called centrifugal force.

The counterforce of the centrifugal force is called the centripetal force. It also acts on every rotating body.

This force is always directed towards the center of the origin of the curve.

The velocity of the object changes its direction and magnitude at any instant of time. But the speed and angular velocity of the object remains the same for uniform circular motion.

So, according to the Newtonian mechanics, it is the inertial force of the body responsible for the centripetal force.

5 0
3 years ago
I have a special thermos that has a vacuum chamber between my hot soup and its outside wall. Because my soup is isolated from it
bagirrra123 [75]

Answer:

C. My soup will cool down because of radiation.

Explanation:

Since, there is vacuum between hot soup and its outside wall, then heat can not flow through conduction and convection.

The heat then only flows through radiation.

Therefore, the soup will not cool down because of convection or conduction by because of radiation.

7 0
3 years ago
In lightning , light is seen first and sound is heard later it is due to
Maksim231197 [3]

Answer:

option 4

Explanation:

Light's velocity in air ( 3 × 10^8 m/s ) is much greater than sound's velocity in air ( 343 m/s )

Hence due to difference in velocities , during lightning light is seen first & sound is heard later

8 0
3 years ago
Read 2 more answers
What would happen to Earth if it stopped in its orbit around the sun?
erica [24]
It would crash into the sun
6 0
3 years ago
Read 2 more answers
In a grandfather clock, the second hand moves forward by one second for each half period of the clock’s pendulum.
Maurinko [17]

To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.

In the given problem half of the period is equivalent to 1 second so the pendulum period is,

T= 2s

From the equations describing the period of a simple pendulum you have to

T = 2\pi \sqrt{\frac{L}{g}}

Where

g= gravity

L = Length

T = Period

Re-arrange to find L we have

L = \frac{gT^2}{4\pi^2}

Replacing the values,

L = \frac{(9.8)(2)^2}{4\pi^2}

L = 0.99m

In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,

T = 2\pi \sqrt{\frac{L}{g/6}}

T = 2\pi\sqrt{\frac{6L}{g}}

T = 2\pi \sqrt{\frac{6*0.99}{9.8}}

T  = 4.89s

In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.

6 0
3 years ago
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