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slavikrds [6]
3 years ago
8

HI PLEASE HELP, I ONLY HAVE 10 MINUTES

Physics
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

um ok

?????

i dont like you get rejected

jk u gud

Explanation:

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In ionic bonding, atoms
Genrish500 [490]
Can i have more information?
3 0
3 years ago
A 1kg dictionary is resting on a table that is 1.5m high. How much potential energy
melamori03 [73]

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

P.E = mgh

Substituting into the equation, we have;

P.E = 1*9.8*1.5

P.E = 14.7 Joules.

6 0
3 years ago
In which of the following situation is work being done?
Afina-wow [57]

A wagon is pulled at an angle of 30 degrees to the horizontal.

6 0
3 years ago
Bohr's model is sometimes called the ________ model because it resembles a mini-solar system.
elena-14-01-66 [18.8K]
His model was also called the Planetary model
7 0
3 years ago
Read 2 more answers
If a transmission line in a cold climate collects ice, the increased diameter tends to cause vortex formation in a passing wind.
AleksAgata [21]

Answer:

a) f_1=5.587Hz

b) f_{n+1}-f_n=5.587Hz

Explanation:

The frequency of the n^{th} harmonic of a vibrating string of length <em>L, </em>linear density \mu under a tension <em>T</em> is given by the formula:

f_n=\frac{n}{2L} \sqrt{\frac{T}{\mu}

a) So for the <em>fundamental mode</em> (n=1) we have, substituting our values:

f_1=\frac{1}{2(347m)} \sqrt{\frac{65.4\times10^6N}{4.35kg/m}}=5.587Hz

b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since:

f_{n+1}-f_n=\frac{n+1}{2L} \sqrt{\frac{T}{\mu}}-\frac{n}{2L} \sqrt{\frac{T}{\mu}}=(n+1-n)\frac{1}{2L} \sqrt{\frac{T}{\mu}}=\frac{n}{2L} \sqrt{\frac{T}{\mu}}=f_1=5.587Hz

3 0
3 years ago
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