To what potential should you charge a 3.0 μf capacitor to store 1.0 j of energy?
1 answer:
The energy stored in a capacitor is given by:
where
U is the energy
C is the capacitance
V is the potential difference
The capacitor in this problem has capacitance
So if we re-arrange the previous equation, we can calculate the potential V that should be applied to the capacitor to store U=1.0 J of energy on it:
where
U is the energy
C is the capacitance
V is the potential difference
The capacitor in this problem has capacitance
So if we re-arrange the previous equation, we can calculate the potential V that should be applied to the capacitor to store U=1.0 J of energy on it:
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Answer:
Max speed =
Max acceleration =
Explanation:
Given the description of period and amplitude, the SHM could be described by:
and its angular velocity can be calculated doing the derivative:
And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):
and is given in m/s.
Then the maximum speed is obtained when the cosine function becomes "1", and that gives:
Max speed =
The acceleration is found from the derivative of the velocity expression, and therefore given by:
and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:
Max acceleration =