Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
x = 29
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the 3 given angles and equate to 180
x + 2x + 2 + 3x + 4 = 180, that is
6x + 6 = 180 ( subtract 6 from both sides )
6x = 174 ( divide both sides by 6 )
x = 29
Answer: 1 1/2
Step-by-step explanation:
Answer:
the term is separated by minus (-) and plus (+) .
therefore this term is trinomial.
Answer:
x
19/6
Step-by-step explanation:
1. Multiply both sides by 6 (the LCM of 6,3)
5/2 + 3-x <= 2(x-2)
2. Simplify 5/2+3-x to 11/2-x
11/2 - x<=2 (x-2)
3. Expand.
11/2-x<= 2x-4
4. Add x to both sides.
11/2<= 2x-4+x
5. Simplify 2x-4+x to 3x-4.
11/2<=3x-4
6. Add 4 to both sides.
11/2+4<=3x
7. Simplify 11/2+4 to 19/2
19/2<=3x
8. Divide both sides by 3
19/2 /3 <=x
9. Simplify 19/2 /3 to 19/2*3
19/2*3<=x
10. Simplify 2*3 to 6
19/6<=x
11. Switch sides.
x>= 19/6
Hope this helps!
