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Artyom0805 [142]
3 years ago
14

Why food cook faster with salt water than cook with pure water​

Physics
2 answers:
Shalnov [3]3 years ago
7 0
When salt is added, it makes it harder for the water molecules to escape from the pot and enter the gas phase, which happens when water boils
user100 [1]3 years ago
5 0

Answer:

oil heats faster

Explanation:

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What are 3 types of cells that helper T cells produce upon being an alarmed of an antigen? Thanks for your help!! :)
Svetllana [295]
Whenever these are an alarming due to a foreign antigen, the Helper T cells, Memory T cells, and Cytotoxic T cells are being produced. Helper T cells to recognize the specific foreign antigen that is entering the body, Memory T cells to remember the specific foreign antigen that is attacking, and Cytotoxic T cells that are for the destruction of the foreign cells and produce cytokines to attract macrophages
5 0
3 years ago
A luggage handler pulls a 20.0 kgkg suitcase up a ramp inclined at 32.0 ∘∘ above the horizontal by a force F⃗ F→ of magnitude 16
Nuetrik [128]

Answer:

a)    W₁ = 8242.2 J, b)      W₁ = 8242.2 J , c)  W₃ = 0 , d)  W₄ = -189.51 J  ,

f) v = 27.24 m / s

Explanation:

a) Work is defined by

         W = F. d ​​= F d sin θ

where angle is between force and displacement

n this case the suitcase is going up and the outside F is parallel to the plane, so the angle is zero and the cosine is 1

         W = F d

           

Let's calculate

         W = 169 3.8

          W₁ = 8242.2 J

b) the gravitational force is vertical so it has an angle with respect to the horizontal parallel to the plane of

           θ’= 90 - θ

           θ'= 90-32 = 58º

           

           W = m g d thing θ ’

            W = 20 9.8 3.8 thing (180 + tea ’) =

            W = 744.8 cos (180 + 32)

            W₂ = -631.6 J

c) The normal work, as it has 90º with respect to the displacement, its work is zero

         W₃ = 0

d) the work of the friction force

           

Let's write Newton's second law the Y axis

         N- Wy = 0

         Cos 32 = Wy / W

          N = W cos 32

The expression for friction force is

         fr = μ N

         fr = μ mg cos 32

         fr = 0.300 20 9.8 cos (32)

         fr = 49.87 N

The work of the friction force

         W = fr d cos 180

         W₄ = -49.87 3.8

          W₄ = -189.51 J

 

E) The total work

         W = W₁ + W₂ + W₃ + W₄

         W = 8242.2- 631.6 + 0 -189.51

          W_total = 7421.09 J

F) Usmeosel theorem of work and energy

          W = ΔK

          W = ΔK = ½ m v² - 0

          v =√ 2W / m

          v = √ (2 7421.09 / 20)

          v = 27.24 m / s

5 0
4 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
Convert 150,000mm to km
Gwar [14]

.15 km.  It goes in this way from largest to least:  Kilometers, Hectometers, decameters, meters, decimeters, centimeters, and finally millimeters.  When you are going up in measures you move the decimal point one space to the left for each measure you pass.  It is vice-versa for going down these measures plz mark brainliest.

5 0
4 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
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