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mamaluj [8]
2 years ago
12

A falcon is hovering above the ground, then suddenly pulls in its wings and begins to fall toward the ground. Air resistance is

not negligible. Identify the forces on the falcon.
Physics
1 answer:
abruzzese [7]2 years ago
7 0

Answer:

As the falcon begins to fall towards the ground, then there will be two forces acting on it, 1) weight of the falcon acting downward and 2) the drag force acting on it due to it's motion through the air.

Explanation:

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A swing has a period of 10 seconds. What is its frequency ?
kow [346]

Frequency = 1 / (period)

Frequency = 1 / (10 seconds) = (1/10) ( / second) = 0.1 per second = <em>0.1 Hz</em>.


4 0
2 years ago
Thing 1 and Thing 2 push with a force of 2000 N to move a rather small 500 kg elephant 30 m across the kitchen floor. How much w
Amanda [17]

Answer:

60000 J

Explanation:

Assuming the force is applied parallel to the displacement of the elephant, the work done to move it across the floor is

W=Fd

where

F = 2000 N is the force applied

d = 30 m is the displacement of the elephant

Substituting the numbers into the formula, we find

W=(2000 N)(30 m)=60,000 J

3 0
3 years ago
PLEASE HELP
Gennadij [26K]

Answer:

3.675 m

Explanation:

a_{x} =0 v_{xo}=100 a_{y} =-g  v_{yo}=0

X-direction     | Y-direction

R=x_{o}+ v_{xo} t  | y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2

75=100t         |y=0+0+\frac{1}{2} (9.8)(0.75)

\frac{75}{100} =t             | y=3.675 m

0.75s=t              

Hope it helps

3 0
3 years ago
What affect does a tripling of the net force have upon the acceleration of the object ? Be quantitative
vovikov84 [41]
The formula of net Force is:
F = ma
where m is the mass of the object
a is the acceleration of the object

so if we triple the net force applied to the object:
3F = ma
a = 3F / m

so the acceleration will also be tripled. because from the equation, the force is directly proportional to the acceleration
5 0
3 years ago
Monochromatic light is incident on (and perpendicular to) two slits separated by 0.200 mm, which causes an interference pattern
marusya05 [52]

Answer:

I = 0.636*Imax

Explanation:

(a) To find the fraction of the maximum intensity at a distance y from the central maximum you use the following formula:

I=I_{max}cos^2(\frac{\pi d}{\lambda L}y)   (1)

I: intensity of light

Imax: maximum intensity of light

d: separation between slits = 0.200mm = 0.200 *10^-3 m

L: distance from the screen = 613cm = 0.613 m

y: distance to the central peak of the interference pattern

λ: wavelength of light = 656.3 nm = 656.3 *10^-9 m

You replace the values of all variables in the equation (1):

I=I_{max}cos^2(\frac{\pi (0.200*10^{-3}m)}{(656.3*10^{-9}m)(0.613m)}0.600m)\\\\I=I_{max}cos^2(937.06)=0.636I_{max}

Hence, the fraction of the maximum intensity is I = 0.636*Imax

6 0
3 years ago
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