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Hunter-Best [27]
2 years ago
15

What is the main pathway by which energy is wastefully transferred from a light bulb?

Physics
1 answer:
HACTEHA [7]2 years ago
4 0

Answer: The energy transfer occurs by convection (particle movement) and by radiation of heat and light. The potential energy from the batteries in the torch is transferred to the filament of the bulb. The energy is transferred to the surroundings as thermal energy and light

Explanation:

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Một ô tô đi với vận tốc 60 km/h trên nửa phần đầu của đoạn đường AB. Trong nửa đoạnđường còn lại ô tô đi nửa thời gian đầu với v
melamori03 [73]

Answer:

Huhfgyyeyvvucvyehukfsdjbjz/////???

4 0
3 years ago
Find the distance between two slits that produces the first minimum for 410-nm violet light at an angle of 45.0°
Tpy6a [65]

Answer:

Distance between slits, d=2.89\times 10^{-7}\ m  

Explanation:

It is given that,

Wavelength, \lambda=410\ nm=410\times 10^{-9}\ m

Angle, \theta=45

We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :

d\ sin\theta=(n+\dfrac{1}{2})\lambda

For first minimum, n = 0

So, d\ sin\theta=(\dfrac{1}{2})\lambda

d is the distance between slits

So, d=\dfrac{1/2\lambda}{sin\theta}

d=\dfrac{1/2\times 410\times 10^{-9}}{sin(45)}

d=2.89\times 10^{-7}\ m

So, the distance between two slits is 2.89\times 10^{-7}\ m. Hence, this is the required solution.

6 0
3 years ago
Mateo and Jackie were on a playground rolling some different-sized balls to get them to crash. They used a tennis ball (the same
creativ13 [48]

Answer:

In crash one, because the pink soccer ball had more mass, so it would have a stronger force.

6 0
2 years ago
How does sound travel through<br> different mediums?
Kryger [21]

Explanation:

high -in solid

medium - in liquid

low - in air

3 0
3 years ago
Three noise sources produce volume (loudness) levels of 70, 73, and 80 dB when acting separately. When the sources act together,
Mashutka [201]

Sound at 70 dB is 70 dB louder than the human reference level.  That's 10⁷ times as much as the reference sound power.

Sound at 73 dB is 73 dB louder than the human reference level.  That's 10⁷.³  or  2 x 10⁷  times as much as the reference sound power.

Sound at 80 dB is 80 dB louder than the human reference level.  That's 10⁸  or 10 x 10⁷ times as much as the reference sound power.

Now we can adumup:

Intensity of all 3 sources = (10⁷) + (2 x 10⁷) + (10 x 10⁷)

Intensity = (13 x 10⁷) times the sound power reference intensity.

Intensity in dB = 10 log (13 x 10⁷) = 10 (7 + log(13)

Intensity = 70 + 10 log(13)

Intensity = 70 + 10 (1.114)

Intensity = 70 + 11.14

Intensity = <em>81.14 dB</em>

<em>______________________________________</em>

Looking at the questioner's profile, I seriously wonder whether I'll ever get a comment in return from this creature, and how I'll ever find out if my solution is correct.  For that matter, I'm also seriously questioning how and whether my solution will ever be used for anything.

8 0
3 years ago
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