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Paraphin [41]
4 years ago
15

What minimum frequency of light is needed to eject a photoelectron from atoms of of platinum, which require at least 9.08 x 10^-

19 J/photon?
Chemistry
1 answer:
denis-greek [22]4 years ago
3 0

Answer:

f = 1.37 × 10¹⁵ Hz

Explanation:

Given data:

Energy of photon = 9.08 × 10⁻¹⁹ j

Frequency = ?

Solution:

Formula:

E = h. f

f = frequency

h = planck's constant

E = energy

Now we will put the values in formula.

h = 6.63  × 10⁻³⁴ j.s  

9.08 × 10⁻¹⁹ j =  6.63  × 10⁻³⁴ j.s  × f

f = 9.08 × 10⁻¹⁹ j / 6.63  × 10⁻³⁴ j.s

f = 1.37 × 10¹⁵ s⁻¹

s⁻¹ = Hz

f = 1.37 × 10¹⁵ Hz

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